Answer:
The maximum profit is when they make 10 units of A and 2 units of B.
Step-by-step explanation:
Let x is units of milk
Let y units of cacao
Given that :
The company's production plant has a total of 22 units of milk and 46 units of cacao available.
2x + y ≤ 22 (2 unit of milk for each of A and 1 for B; 22 units available)
4x + 3y ≤46 (4 unit of milk for each of A and 3 for B; 46 units available
Graph the constraint equations and find the point of intersection to determine the feasibility region.
The intersection point (algebraically, or from the graph) is (10, 2)
The objective function for the problem is the total profit, which is $6.2 per unit for A and $4.2 per unit for B: 6.2x + 4.2y.
Hence, we substitute (10, 2) into the above function:
6.2*10 + 4.2*2 = 70.4
The maximum profit is when they make 10 units of A and 2 units of B.
If the equation is 8x-3y-5=0
Then the slope intercept form would be:
y=8/3x-5/3
Set contain all the elements present in both the sets.
<u>Step-by-step explanation:</u>
Definition:
The union of two mathematical sets can be defined as the set that consists of all the elements present in both the sets without the repetition of elements.
Consider, A and B be the sets.
A = {1,7,5,6,0}
B = {2,3,4,5,6}
U is the symbol of union of sets, so A U B = {1,2,3,4,5,6,7,0}
Here 5 and 6 are the elements present in both the sets, so written only once in the set of A U B.
Option 3
The solution for given expression is 
<h3><u>
Solution:</u></h3>
Given that we have to divide,
---- (A)
Let us first factorize each term and then solve the sum
Using 
----- (1)
----- (2)
---- (3)
---- (4)
Now substituting (1), (2), (3), (4) in (A) we get,
To do division with fractions, we turn the second fraction upside down and change the division symbol to a multiplication symbol at the same time. Then we treat this as a multiplication problem, by multiplying the numerators and the denominators separately.
On cancelling terms we get,
Thus option 3 is correct
This is what it shows for the solution. Hope this helps.
