I would be difficult to remove an electron from a Noble or Inert Gas (also known as the group 8 or 0 elements). This is because they all have filled outermost shells and as such the outermost shell would be held tightly to the nucleus and as such make it difficult to remove. Examples Helium, Neon, Argon, Xenon, Krypton and Radon
Answer:
1,620 J.
Explanation:
- The amount of heat added to a substance (Q) can be calculated from the relation:
<em>Q = m.c.ΔT.</em>
where, Q is the amount of heat released from ethanol cooling,
m is the mass of ethanol (m = 60.0 g),
c is the specific heat of ethanol in the liquid phase, since the T is cooled below the boiling point and above the melting point (c = 1.0 J/g °C),
ΔT is the temperature difference (final T - initial T) (ΔT = 43.0 °C – 70.0 °C = - 27.0 °C).
<em>∴ Q = m.c.ΔT</em> = (60.0 g)(1.0 J/g °C)(- 27.0 °C) = - 1620 J.
<em>The system releases 1620 J.</em>
There are 300 light particles in an airtight container. The adjustment that would increase the speed of the particle is keeping the pressure constant and increasing the temperature. Option B is correct.
The speed of a particle is the distance traveled by one molecule of a substance. Particles travel as a result of the kinetic energy they possess.
The kinetic energy attributed to each particle rises as the temperature rises.
As a result, in 300 light particles, the particles will travel more quickly when the temperature is increased while the pressure of the particle remains constant.
Therefore, we can conclude that the adjustment that would increase the speed of the particles is keeping the pressure constant and increasing the temperature.
Learn more about particles here:
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Consider the following homogenous reaction:
aA + bB ⇔ cC + dD
The equilibrium constant is written as:
Kc = ([C]^c * [D]^d) / ([A]^a * [B]^b)
Therefore the equilibrium constant is the ratio of the concentration of the products to concentration of the reactants at equilibrium.
For a heterogenous reaction, the species that are not in the same physical state as the rest of the chemical species are omitted from the expression. Considering the previous reaction, if reactant A was solid and the remaining were gaseous, the expression will be:
Kc = ([C]^c * [D]^d) / [B]^b
(P1)(V1)=(P2)(V2)
(2.52 atm)(125 L)=(1.50 atm)(x L)
(315)/(1.50)=(V2)
V2=210 L