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Leona [35]
4 years ago
5

AL2O3 and ZNO are which oxides​

Chemistry
1 answer:
Nesterboy [21]4 years ago
6 0

Answer:

<em><u>Metal oxides</u></em>

Explanation:

Al2O3, ZnO and SnO are typical amphoteric oxides. Metal oxides are usually basic and they react with acids to form their respective salts

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3 years ago
If you began a reaction with the following ions in solution, what would be the net ionic equation?
Mumz [18]

Answer:

2 PO₄³⁻(aq) + 3 Fe²⁺(aq) ⇒ Fe₃(PO₄)₂

Explanation:

Let's consider the complete ionic equation between the ions present. It includes all the ions and the insoluble compounds (Fe₃(PO₄)₂ is insoluble).

Na⁺(aq) + 2 PO₄³⁻(aq) + 3 Fe²⁺(aq) + NO₃⁻(aq) ⇒ Fe₃(PO₄)₂ + Na⁺(aq) + NO₃⁻(aq)

The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the insoluble compounds.

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6 0
3 years ago
What is the molar concentration (in moles/L) of a solution made with 3.744 g of Mg(NO3)2 dissolved in enough water to make 50.0
Annette [7]

Answer:

The molar concentration of a solution made with 3.744 g of Mg(NO₃)₂ dissolved in enough water to make 50.0 mL of solution is 0.5 \frac{moles}{L}

Explanation:

Molarity or Molar Concentration is the number of moles of solute that are dissolved in a certain volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

molarity=\frac{number of moles}{volume}

In this case:

  • Mg: 24.3 g/mole
  • N: 14 g/mole
  • O: 16 g/mole

So, the molar mass of Mg(NO₃)₂ is:

Mg(NO₃)₂= 24.3 g/mole + 2*(14 g/mole + 3*16 g/mole)= 148.3 g/mole

So, if you have 3.744 g of Mg(NO₃)₂, you can apply the following rule of three: if 148.3 grams of Mg(NO₃)₂ are present in 1 mole, 3.744 grams in how many moles are present?

moles=\frac{3.744 grams*1mole}{148.3 grams}

moles= 0.025

Then you have:

  • number of moles=0.025
  • volume= 50 mL= 0.05 L (being 1,000 mL= 1 L)

Replacing in the definition of molarity:

molarity=\frac{0.025 moles}{0.05 L}

you get:

molarity=0.5 \frac{moles}{L}

<u><em>The molar concentration of a solution made with 3.744 g of Mg(NO₃)₂ dissolved in enough water to make 50.0 mL of solution is </em></u>0.5 \frac{moles}{L}<u><em></em></u>

6 0
3 years ago
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