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Leona [35]
3 years ago
5

AL2O3 and ZNO are which oxides​

Chemistry
1 answer:
Nesterboy [21]3 years ago
6 0

Answer:

<em><u>Metal oxides</u></em>

Explanation:

Al2O3, ZnO and SnO are typical amphoteric oxides. Metal oxides are usually basic and they react with acids to form their respective salts

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Which tool is used to detect yellow light rays emitted by stars from outer space?
elixir [45]
Answer A

x-ray optical telescope.

hope this helps!.

3 0
3 years ago
A lead ball is added to a graduated cylinder containing 30.8 ml of water, causing the level of the water to increase to 89.9 ml.
enot [183]

A lead ball added to a graduated cylinder containing 30.8 ml of water, causing the level of the water to increase to 89.9 ml, has a volume of 59.1 ml.

Volume is defined as the amount of space that matter occupies. There are three different ways to find the volume:

1) Volume by Space - by measuring its physical dimensions

2) Volume by Density and Mass - by dividing its weight by its density

3) Volume by Displacement - by measuring the volume displaced when immersed in a liquid or gas

To solve for the volume of the lead ball, we can use the displacement method by subtracting the initial volume from the final volume.

If the level of the water increased from 30.8 ml to 89.9 ml upon adding the lead ball, the displaced volume is:

volume = final volume - initial volume

volume = 89.9 - 30.8

volume = 59.1 ml

Hence, the volume of the lead ball, using displacement method, is 59.1 ml.

To learn more about volume by displacement: brainly.com/question/1945909

#SPJ4

3 0
2 years ago
A sample of gas is held at 1000C at a volume of 20 L. If the volume is increased to 40 L, what is the new temperature of the gas
kaheart [24]

Answer:

The new temperature will be 2546 K or 2273 °C

Explanation:

Step 1: Data given

The initial temperature = 1000 °C =1273 K

The volume = 20L

The volume increases to 40 L

Step 2: Calculate the new temperature

V1/T1 = V2/T2

⇒with V1 = the initial volume = 20L

⇒with T1 = the initial temperature = 1273 K

⇒with V2 = the increased volume = 40L

⇒with T2 = the new temperature = TO BE DETERMINED

20L/ 1273 K = 40L / T2

T2 = 40L / (20L/1273K)

T2 = 2546 K

The new temperature will be 2546 K

This is 2546-273 = 2273 °C

Since the volume is doubled, the temperature is doubled as well

8 0
3 years ago
Dbv-qyag-dsc.join this now on meet​
Rasek [7]

Answer:

Don't post any question if isn't related to the topic or to your homework or assignment.

Explanation:

7 0
3 years ago
Consider a simple reaction in which a reactant AA forms products: A→productsA→products What is the rate law if the reaction is z
levacccp [35]

Answer :

The rate law expression for zero order reaction will be:

Rate=k[A]^0

The rate law expression for first order reaction will be:

Rate=k[A]^1

The rate law expression for second order reaction will be:

Rate=k[A]^2

Zero order reaction : There is no affect on the rate law.

First order reaction : The rate law becomes doubled.

Second order reaction : The rate law becomes quadrupled.

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The given reaction is:

A\rightarrow Products

The rate law expression for zero order reaction will be:

Rate=k[A]^0

The rate law expression for first order reaction will be:

Rate=k[A]^1

The rate law expression for second order reaction will be:

Rate=k[A]^2

Now we have to determine that if doubling of the concentration of A then the rate of reaction will be:

As we know that the zero order reaction does not depend on the concentration of reactant. So, there is no affect on the rate law.

As we know that the first order reaction depend on the concentration of reactant. So, the rate law becomes doubled.

As we know that the second order reaction depend on the concentration of reactant. So, the rate law becomes quadrupled.

5 0
4 years ago
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