Question

Which equation, when graphed, has x-intercepts at (−1, 0) and (−5, 0) and a y-intercept at (0, −30)?

Answer 1

Answer:

Option A

Step-by-step explanation:

The equation has x intecepts at -1 and -5.

Hence function would be of the form

a(x+1)(x+5) for some real a.

To find a, let us use y intercept

When x =0 we have y =a(1)(5)

y intercept is given as -30

i.e. 5a = -30

a=-6

So

f(x) = -6(x+1)(x+5)

Option A is the right answer.

Answer 2

The first one is correct. If you plug zero in for the x's, you will get the y intercept (since the value of x on the y axis is zero). Setting the two factors each to zero and solving you get the x intercepts -1 and -5.