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andriy [413]
2 years ago
15

Can someone pls help

Mathematics
2 answers:
Ilia_Sergeevich [38]2 years ago
7 0
I’m pretty positive it’s C: commutative property
Irina-Kira [14]2 years ago
5 0

Answer:

C

Step-by-step explanation:

You might be interested in
Solve 8w – 3r = 45 for r
bogdanovich [222]
<span>8w – 3r = 45 
3r = 8w - 45
  r = 8w/3 - 15
hope it helps</span>
7 0
3 years ago
the diameter of a piston for an automobile is 3 11/16in with tolerence of 1/64in. find the upper and lower limits of the pistons
padilas [110]

Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

<u>Upper Limit</u>

\dfrac{11}{16} +  \dfrac{1}{64}

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

\dfrac{11*4}{16*4} +  \dfrac{1}{64}

\dfrac{11*4}{16*4} +  \dfrac{1}{64} Which results in

\dfrac{44}{64} +  \dfrac{1}{64}

With a final result for the fractions of 45/64

So the upper tolerance = 3 45/64

<u>Lower Tolerance</u>

Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

\dfrac{11}{16} - \dfrac{1}{64}

Your answer should be 3 and 43/64


4 0
3 years ago
Please answer as soon as possible, whoever is first gets the brainliest
Jlenok [28]

Answer:

I'm not sure what to do here

Step-by-step explanation:

7 0
3 years ago
Independent assessment 3
Akimi4 [234]
It’s blurry!!!!!!!!!!!
8 0
2 years ago
the length of a rectangle is 5 inches more then the width. the area of the rectangle is equal to 2 inches more than 4 times the
Svet_ta [14]
P = 2(L + W)
L = W + 5
A = 4P + 2

P = 2(W + 5 + W)
P = 2(2W + 5)
P = 4W + 10

A = 4P + 2
A = 4(4W + 10) + 2
A = 16W + 42

A = L * W
A = W(W + 5)
A = W^2 + 5W

W^2 + 5W = 16W + 42
W^2 + 5W - 16W - 42 = 0
W^2 - 11W - 42 = 0
(W + 3)(W - 14) = 0

W - 14 = 0
W = 14 <==

L = W + 5
L = 14 + 5
L = 19 <==

P = 2(19 + 14)
P = 2(33)
P = 66

A = L * W
A = 19 * 14
A = 266

answer : length = 19, width = 14....perimeter = 66....area = 266
5 0
3 years ago
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