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3 years ago

The mimentum of a 10 kg object moving at a velocity of 20m/s

Physics

1 answer:

Wewaii [24]3 years ago

4 0

Answer:

200kgm/s

Explanation:

Momentum of a body is the product of mass and its velocity. It is also equal to impulse of a force which is the product of force and time.

Momentum = mass x velocity

P = mv

Where

m = 10kg , v = 20m/s

P = 10kg × 20m/s

P = 200kgm/s

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Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 4.50 m above

Virty [35]

$8.98×10^6\:\text{m}$

Explanation:

First we need to find the acceleration due to gravity on the planet. The wrench took 0.809 s to fall from a height of 4.50 m so we can use the equation

$y = -\frac{1}{2}gt^2$

Solving for g, we get

$g = -\dfrac{2y}{t^2} = -\dfrac{2(-4.50\:\text{m})}{(0.809\:\text{s})} = 13.8\:\text{m/s}^2$

Recall that the acceleration due to gravity on a planet's surface can be written as

$g = G\dfrac{M_p}{R_p^2}$

We can express the mass of the planet $M_p$ in terms of its density $\rho$ as follows:

$M_p = \rho \left(\dfrac{4\pi}{3}R_p^3\right) = \dfrac{4\pi}{3}\rho R_p^3$

The expression for g then becomes

$g = \dfrac{G}{R_p^2} \left(\dfrac{4\pi}{3}\rho R_p^3\right) = \dfrac{4\pi G}{3}\rho R_p$

Solving for $R_p,$ we get

$R_p = \dfrac{3g}{4\pi G\rho}$

$\:\:\:\:\:\:\:= \left[\dfrac{3(13.8\:\text{m/s}^2)}{4\pi (6.674×10^{-11}\:\text{Nm}^2\text{/kg}^2)(5500\:\text{kg/m}^3)}\right]$

$\:\:\:\:\:\:\:= 8.98×10^6\:\text{m}$

3 0

3 years ago

Can someone help me please? I’m so confused

Svetradugi [14.3K]

Answer:

what do you need help with? Like which type of print each image is?

Explanation:

5 0

3 years ago

Please help! 20 points! Name an example when you personally have experienced the Doppler effect.

Anika [276]

When I ride the train, the song of the train whistle is an example of the Doppler Effect. Because a train is at the center of sound waves it produces, which radiate in concentric circles around it, there is no difference between the sound heard by someone on the platform, and the sound of the train as heard by someone standing behind the caboose.

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4 years ago

A 70.0 kg base runner moving at a speed of 4.0 m/s begins his slide into second base. The coefficient of friction between his cl

Andre45 [30]

Answer:

B. 560 J

J. 1.2 m

Explanation:

v = Final velocity = 0

u = Initial velocity = 4 m/s

$\mu$ = Coefficient of friction = 0.7

m = Mass of runner = 70 kg

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

Kinetic energy is given by

$K=\dfrac{1}{2}m(v^2-u^2)\\\Rightarrow K=\dfrac{1}{2}\times 70\times (0^2-4^2)\\\Rightarrow K=-560\ \text{J}$

The mechanical energy lost is 560 J

Acceleration is given by

$a=-\mu g\\\Rightarrow a=-0.7\times 9.81\\\Rightarrow a=-6.867\ \text{m/s}^2$

From kinematic equations we get

$v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-4^2}{2\times -6.867}\\\Rightarrow s=1.165\approx 1.2\ \text{m}$

The runner slides for 1.2 m

4 0

3 years ago

How Many Significant Digits are in 0.0217

Bumek [7]

Answer:

The number 0.0217 has 3 significant digits

Explanation:

Significant Digits

These are digits that contribute to the significance of the number. Some rules apply to discard the non-significant digits like:

Leading zeros
Trailing zeros (with exceptions)

Our number is 0.0217 has two leading zeros before the 2 because they only occupy space to indicate the order of magnitude of the number. Only the 2,1,7 are significant digits, thus

The number 0.0217 has 3 significant digits

7 0

3 years ago