A projectile fired upward from the Earth's surface will usually slow down, come momentarily to rest, and return to Earth. For a certain initial speed, however it will move upward forever, with its speed gradually decreasing to zero just as its distance from Earth approaches infinity. The initial speed for this case is called escape velocity. You can find the escape velocity v for the Earth or any other planet from which a projectile might be launched using conservation of energy. The projectile of mass m leaves the surface of the body of mass M and radius R with a kinetic energy Ki = mv²/2 and potential energy Ui = -GMm/R. When the projectile reaches infinity, it has zero potential energy and zero kinetic energy since we are seeking the minimum speed for escape. Thus Uf = 0 and Kf = 0. And from conservation of energy,
Ki + Ui = Kf + Uf
mv²/2 -GMm/R = 0
∴ v = √(2GM/R)
This is the expression for escape velocity.
I think the answer is strong force.
The distance a dropped object falls, with gravity and no air resistance:
Distance = (1/2) (acceleration) (falling time)²
Without air resistance, the horizontal motion has no effect on the fall.
Acceleration of Earth gravity = 9.8 m/s²
Distance = (1/2) (acceleration) (falling time)²
Distance = (1/2) (9.81 m/s²) (3.0 s)²
Distance = (0.5) x (9.81 m/s²) x (9.0 s²)
Distance = (0.5 x 9.81 x 9.0) (m-s² / s²)
Distance = 44.15 meters
We don't care how fast the bird was flying horizontally. It doesn't change anything. (It DOES determine how far ahead of the drop point the clam hits the ground. Most problems like this ask for that distance. This one didn't.)
The resistance would increase.
Answer:
Explanation:
Atoms naturally bond with each other in an attempt to have 8 or zero valence electrons. This occurs in salts, covalent bonds, and mettalic bonds. This is how the octet rule demonstrates why atoms bond.
Hope this helps!
