Answer: The force of the engines is 5700N
Explanation:
By the second Newton's law, we have that:
F = m*a
Force equals mass times acceleration.
In this case, we have:
m = 1400kg
a = 3 m/s^2
And the force will be equal to the force of the engines, f, plus the force of the current, -1500 N (because this is pushing you back, so it is in the opposite direction than f), then we have:
F = f - 1500N
Then we have the equation:
f - 1500N = 1400kg*3m/s^2 = 4200N
f - 1500N = 4200N
f = 4200N + 1500N = 5700N
The force of the engines is 5700N
Answer:
The speed of water flow inside the pipe at point - 2 = 34.67 m / sec
Explanation:
Given data
Diameter at point - 1 = 3.2 cm
Velocity at point - 1 = 1.1 m / sec = 110 cm / sec
Diameter at point - 2 = 0.57 cm
Velocity at point - 2 = ??
We know that from the continuity equation the rate of flow is constant inside a pipe between two points.
Thus
⇒
×
=
× 
⇒
×
×
=
⇒
×
=
× 
⇒
× 110 =
× 
⇒
= 3467 cm / sec
⇒
= 34.67 m / sec
Thus the speed of water flow inside the pipe at point - 2 = 34.67 m / sec
Answer:
a-1 Graph is attached. The relation is linear.
a-2 The corresponding height for 68 kPa Pressure is 7.54 m
a-3 The corresponding weight for 68 kPa Pressure is 1394726kg
b The original height of the column is 5.98 m
Explanation:
Part a
a-1
The graph is attached with the solution. The relation is linear as indicated by the line.
a-2
By the equation

Here
- P is the pressure which is given as 68 kPa.
- ρ is the density of the oil whose SG is 0.92. It is calculated as

- g is the gravitational constant whose value is 9.8 m/s^2
- h is the height which is to be calculated

So the height of column is 7.54m
a-3
By the relation of volume and density

Here
- ρ is the density of the oil which is 920 kg/m^3
- V is the volume of cylinder with diameter 16m calculated as follows

Mass is given as

So the mass of oil leading to 68kPa is 1394726kg
Part b
Pressure variation is given as

Now corrected pressure is as

Finding the value of height for this corrected pressure as

The original height of column is 5.98m
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Answer: Attach it to clothing, personal flotation device or the person's person.
Explanation:
This particular Question or problem has to do with the rules and regulations or laws governing the use of Personal Watercraft(PWC) in the state of Florida in the United States of America. Hence, one of the rules that is applicable to the use of boats and waterways or the use of personal watercraft in Florida is that in florida, if ones pwc is equipped with an engine cut-off lanyard the person operating it must ATTACH IT TO THE CLOTHING, PERSONAL FLOATATION DEVICE IR THE OPERATORS' PERSON.
Another rule band the use of flammable personal flotation device with Personal Watercraft(PWC) in the state of Florida. All this rules and guildlines are made to limit or minimize hazards.