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zysi [14]
3 years ago
14

A force of 25 newtons moves a box a distance of 4 meters in 5 seconds.

Physics
2 answers:
Nina [5.8K]3 years ago
7 0

Answer:

blub

Explanation:

Simora [160]3 years ago
5 0

By definition, we have that the work done is given by:

W = F * d

Where,

F: force in the direction of displacement

d: displaced distance

Substituting values we have:

W = (25) * (4)\\W = 100 Nm

Then, the power is given by:

P = \frac{W}{t}

Where,

t: time

Substituting values we have:

P = \frac{100}{5}

P = 20\frac{Nm}{s}

Answer:

The work done on the box is 100 Nm, and the power is 20 Nm/s.

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Stolb23 [73]

Answer:

cell division

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2 years ago
Read 2 more answers
A toaster using a Nichrome heating element operates on 120 V. When it is switched on at 28 ∘С, the heating element carries an in
sukhopar [10]

Answer:

The final temperature of the element = 262.67°C

The power dissipated in the heating element initially = 163.21 W

The power dissipated in the heating element when the current reaches 1.23 A = 147.60 W

Explanation:

Our given parameters include;

A Nichrome heating element operates on 120 V.

Voltage (V) = 120V

Initial Current (I₁) = 1.36 A

Initial Temperature (T₁) = 28°C

Final Current (I₂) = 1.23 A

Final Temperature (T₂) = unknown ????

Temperature dependencies of resistance is given by:

R_{T(2)}=R_1[1+\alpha (T_2-T_1)]            ----------------------    (1)

in which R₁ is the resistance at temperature T₁

R_{T(2) is the resistance at temperature T₂

Given that V= IR

R = \frac{V}{I}

Therefore, the resistance at temperature 28°C is;

R_{28}= \frac{120V}{1.36A}

= 88.24Ω

R_{T(2) = \frac{120V}{1.23A}

= 97.56Ω

From (1) above;

R_{T(2)}=R_1[1+\alpha (T_2-T_1)]      

97.56 = 88.24 [ 1 + 4.5×10⁻⁴(°C)⁻¹(T₂-28°C)]

\frac{97.56}{88.24}= 1+(4.5*10^{-4})(T-28^0C)

1.1056 - 1 = 4.5×10⁻⁴(°C)⁻¹(T₂-28°C)

0.1056 = 4.5×10⁻⁴(T₂-28°C)

\frac{0.1056}{4.5*10^{-4}}= T-28^0C

T - 28° C = 234.67

T = 234.67 + 28° C

T = 262.67 ° C

(b)

What is the power dissipated in the heating element initially and when the current reaches 1.23 A

The power dissipated in the heating element initially can be calculated as:

P = I²₁R₂₈

P = (1.36A)²(88.24Ω)

P = 163.209 W

P ≅ 163.21 W

The power dissipated in the heating element when the current reaches 1.23 A can be calculated as:

P= I^2_2R_{T^0C

P = (1.23)²(97.56Ω)

P = 147.598524

P ≅ 147.60 W

6 0
2 years ago
Calculate the Latent Heat of Vaporization. (Please see picture attached)
Hunter-Best [27]

Answer:

20 J/g

Explanation:

In this question, we are required to determine the latent heat of vaporization

  • To answer the question, we need to ask ourselves the questions:

What is latent heat of vaporization?

  • It is the amount of heat required to change a substance from its liquid state to gaseous state without change in temperature.
  • It is the amount of heat absorbed by a substance as it boils.

How do we calculate the latent heat of vaporization?

  • Latent heat is calculated by dividing the amount of heat absorbed by the mass of the substance.

In this case;

  • Mass of the substance = 20 g
  • Heat absorbed as the substance boils is 400 J (1000 J - 600 J)

Thus,

Latent heat of vaporization = Quantity of Heat ÷ Mass

                                             = 400 Joules ÷ 20 g

                                             = 20 J/g

Thus, the latent heat of vaporization is 20 J/g

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Which statement accurately describes the outer planets?
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The outer planets have a high gravity due to their large size
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The melting of polar ice is one effect of
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The melting of polar ice is one effect of the greenhouse effect, or also global warming.

The greenhouse effect, as defined by Merriam-Webster, is "the <span>warming of the surface and lower atmosphere of a planet (as Earth or Venus) that is caused by conversion of solar radiation into heat in a process involving selective transmission of short wave solar radiation by the atmosphere, its absorption by the planet's surface, and reradiation as infrared which is absorbed and partly reradiated back to the surface by atmospheric gases".

In short, "</span>the warming of the surface and lower atmosphere of a planet".
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