A force of 25 newtons moves a box a distance of 4 meters in 5 seconds.
2 answers:
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A) The work done by the electric field is zero
B) The work done by the electric field is
C) The work done by the electric field is
Explanation:
A)
The electric field applies a force on the charged particle: the direction of the force is the same as that of the electric field (for a positive charge).
The work done by a force is given by the equation
where
F is the magnitude of the force
d is the displacement of the particle
is the angle between the direction of the force and the direction of the displacement
In this problem, we have:
- The force is directed vertically upward (because the field is directed vertically upward)
- The charge moves to the right, so its displacement is to the right
This means that force and displacement are perpendicular to each other, so
and : therefore, the work done on the charge by the electric field is zero.
B)
In this case, the charge move upward (same direction as the electric field), so
and
Therefore, the work done by the electric force is
and we have:
is the magnitude of the electric force. Since
is the magnitude of the electric field
is the charge
The electric force is
The displacement of the particle is
d = 0.660 m
Therefore, the work done is
C)
In this case, the angle between the direction of the field (upward) and the displacement (45.0° downward from the horizontal) is
Moreover, we have:
(electric force calculated in part b)
While the displacement of the charge is
d = 2.50 m
Therefore, we can now calculate the work done by the electric force:
And the work is negative because the electric force is opposite direction to the displacement of the charge.
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Answer:
Fnet = 14515.2 Newton
Explanation:
Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.
Mathematically, net force is given by the formula;
Where;
- Fnet is the net force.
- Fapp is the applied force.
- Fg is the force due to gravitation.
Given the following data;
Mass = 1,152 kg
Initial velocity, u = 3m/s
Final velocity, v = 17m/s
Time, t = 5 seconds
To find the magnitude of the net force;
First of all, we would determine the acceleration of the car.
Acceleration = (v-u)/t
Acceleration = (17 - 3)/5
Acceleration = 14/5
Acceleration = 2.8m/s
To find the applied force;
Fapp = mass * acceleration
Fapp = 1,152 * 2.8
Fapp = 3225.6 N
Next, we would find the force exerted on the car due to gravity.
Fg = mass * acceleration due to gravity
We know that acceleration due to gravity is equal to 9.8m/s²
Fg = 1152 * 9.8
Fg = 11289.6N
Substituting the values into the equation, we have;
Fnet = 3225.6 + 11289.6
Fnet = 14515.2 Newton