ASAP pls answer I will mark brainiest if right.

Unlike an observational study, an experiment can prove:

Zinaida [17]

A. Cause and effect.

Explanation:

An experiment can prove cause and effect in a study unlike observational studies.

Observational studies is a non-experimental system of investigation.
It helps to identify the causes(independent variable) and the effect(dependent variables).
In observational studies, the variables cannot be controlled and so it is difficult to prove the cause and effect.
An experiment can prove cause and effect because the parameters are tested and can be controlled.

Learn more:

Experiment brainly.com/question/5096428

#learnwithBrainly

3 0

3 years ago

The material through which a mechanical wave travels is

vivado [14]

<h2>Answer: The Medium </h2><h2 />

<u>The medium is the main factor that differentiates a mechanical wave from an electromagnetic wave,</u> since the first can not propagate without its existence, while the second can propagate regardless of whether the medium exists or not.

In addition, it is the medium that will define, the propagation speed of the wave, according to its specific physical characteristics.

6 0

3 years ago

A student has a small piece of steel.

Simora [160]

Answer:

There are different ways to investigate density. In this required practical activity, it is important to:

record the mass accurately

measure and observe the mass and the volume of the different objects

use appropriate apparatus and methods to measure volume and mass and use that to investigate density

Explanation:

5 0

3 years ago

A person wants to make a metronome for music practice. He uses a 35-g object attached to a spring to serve as the time standard.

alukav5142 [94]

To develop this problem it will be necessary to apply the concepts related to the frequency of a spring mass system, for which it is necessary that its mathematical function is described as

$f = \frac{1}{2\pi} \sqrt{\frac{k}{m}}$

Here,

k = Spring constant

m = Mass

Our values are given as,

$m = 35g = 35*10^{-3}kg$

$f = 1 Hz$

Rearranging to find the spring constant we have that,

$k = (2\pi f \sqrt{m})^2$

$k = 4\pi^2 f^2 m$

$k = (4) (\pi)^2 (1) (35*10^{-3})$

$k = 1.38N/m$

Therefore the spring constant is 1.38N/m

7 0

4 years ago

What kind of fluctuations in weather patterns do you expect to see in your area? Will the fluctuations or changes vary by month,

balandron [24]

Prevailing definitions of climate are not much different from “the climate is what you expect, the weather is what you get”. Using a variety of sources including reanalyses and paleo data, and aided by notions and analysis techniques from Nonlinear Geophysics, we argue that this dictum is fundamentally wrong. <span>In addition to the weather and climate, there is a qualitatively distinct intermediate regime extending over a factor of ≈ 1000 in scale.Climate changes is projected to affect individual organisms, populations, ... Overall, there is a strong correlation between topographic slope and velocity from ... the ecosystems they live in—will adapt to these changes, or if they even can.</span>

6 0

4 years ago