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jasenka [17]
3 years ago
5

How do you write 561983 in scientific notation?

Chemistry
1 answer:
Artist 52 [7]3 years ago
7 0

Answer:

5.61983 × 10^5

Explanation:

Move the decimal forward 5 spaces, each time doing so you add 10^(# of spaces moved, in this case 5)

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Which statement best explains what would happen if a reactant were added to a system in equilibrium?
expeople1 [14]

system will shift the equilibrium to the right, towards the side of the products

8 0
3 years ago
Read 2 more answers
Do the chemical bonds between atoms change during cellular respiration?
borishaifa [10]
During cellular respiration, the carbon and hydrogen atoms change partners and bond with oxygen atoms instead. The carbon-hydrogen bonds are replaced by carbon-oxygen and hydrogen-oxygen bonds. As the electrons of these bonds "fall" toward oxygen, energy is released.
6 0
3 years ago
How many milliliters of 4.00 M NaOH are required to exactly neutralize 50.0 milliliters of a 2.00 M solution of HNO3 ?
kramer

Answer: The volume of NaOH required is 25.0 ml

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity HNO_3 = 1

M_1 = molarity of HNO_3 solution = 2.00 M

V_1 = volume of  HNO_3 solution = 50.0 ml

n_2 = acidity of NaOH = 1

M_1 = molarity of NaOH solution = 4.00 M

V_1 = volume of  NaOH solution =  ?

Putting in the values we get:

1\times 2.00\times 50.0=1\times 4.00\times V_2

V_2=25.0ml

Therefore, volume of NaOH required is 25.0 ml

3 0
3 years ago
How are endothermic and exothermic reactions the same how are they different?
svetoff [14.1K]

Endothermic reactions and Exothermic reaction are never the same.

They are both different.

Definitions

<span><span>Endothermic:- reactions that take in energy. For example:- electrolysis, thermal decomposition and the reaction between ethanic acid and sodium carbonate.
</span><span>Exothermic:- reactions that transfer energy to the surroundings. For example:- burning, neutralisation and the reaction between water and calcium oxide.</span></span>
3 0
3 years ago
If the value of kc at 25oc is 3.7108, and the equilibrium concentrations for n2 and h2 are 0.000105 m and 0.0000542 m, respectiv
frez [133]

Equation of decomposition of ammonia:

N2+3H2->2NH3

Euilibrium constant:

Kc=(NH3)^2/((N2)((H2)^3))

As concentration of N2=0.000105, H2=0.0000542

so equation will become:

3.7=(NH3)^2/(0.000105)*(0.0000542)^3

NH3=√(3.7*0.000105*(0.0000542)^3)

NH3=7.8×10⁻⁹

So concentration of ammonia will be 7.8×10⁻⁹.

5 0
3 years ago
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