Answer:
518 mL
Explanation:
We can solve this using Boyle's Law Formula
P1V1 = P2V2
where p1 = initial pressure, p2 = final pressure, v1 = initial volume and v2 = final volume
here , the initial pressure is 1 atm and the initial volume is 725mL
we are given the final pressure 1.4 and we need to find the final volume
so we have p1v1 = p2v2
==> plug in p1 = 1 , v1 = 725 mL and p2 = 1.4
(1)(725) = (1.4)v2
==> multiply 1 and 725
725 = (1.4)(v2)
==> divide both sides by 1.4
v2 = 518
N2 would have a volume of 518mL at 1.4atm
The correct answer is 12.2% BaO.
The solution is found by dividing the mass of the BaO, which is 25.8 grams, by the total mass of the solution, which is 212 grams, then multiplying it by 100 to get the percentage:
6.9 x 10^-4 would be .00069 written in scientific notation
<h3>
Answer:</h3>
495 g K₃N
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.77 mol K₃N
<u>Step 2: Identify Conversions</u>
Molar Mass of K - 39.10 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of K₃N - 3(39.10) + 14.01 = 131.31 g/mol
<u>Step 3: Convert</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
495.039 g K₃N ≈ 495 g K₃N
between two oppositely charged ions