Answer:
Change in volume on changing temperature from 33
to 5
is 5.49 mL
Explanation:
Initial volume of gas = V = 60 mL
Assuming final volume of gas to be V' mL
Initial temperature = T = 33
= 306 K
Final temperature = T' = 5
= 278 K
The relationship between volume and temperature of gas at constant pressure is shown below

Change in volume on changing temperature = 5.49 mL
Explanation:
The pure form of water has a boiling point of 100°C. Boiling point is a physical property of matter and it shows that at such temperature, a liquid substance will change state to vapor.
Pure water is made up of 2 atoms of hydrogen and 1 atom of oxygen. The only intermolecular forces between them is the hydrogen bonds that must be broken for the water to boiling off.
In hydrate, water is present in another form. The water is attached to another compound.
For a pure liquid, the they have reasonably constant boiling point and low boiling range.
Impurities such as the other part of the hydrate causes the elevation of the boiling point and the widening of the boiling range for impure substances.
We are no longer dealing with just hydrogen bonds, other molecular interactions are now involved and they need to be accounted for.
learn more:
Pure substances brainly.com/question/1832352
#learnwithBrainly
Answer:
Explanation:
Given that:
Pressure = 791 mmHg
Temperature = 20.0°C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (20 + 273.15) K = 293.15 K
T = 293.15 K
Volume = 100 L
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 62.3637 L.mmHg/K.mol
Applying the equation as:
791 mmHg × 1.14 L = n × 62.3637 L.mmHg/K.mol × 293.15 K
⇒n of
produced = 0.0493 moles
According to the reaction:-

1 mole of carbon dioxide is produced 1 mole of calcium carbonate reacts
0.0493 mole of carbon dioxide is produced 0.0493 mole of calcium carbonate reacts
Moles of calcium carbonate reacted = 0.0493 moles
Molar mass of
= 100.0869 g/mol
The formula for the calculation of moles is shown below:
Thus,

Impure sample mass = 5.28 g
Percent mass is percentage by the mass of the compound present in the sample.
Answer:
58mL
Explanation:
Given parameters:
Density of water = 1g/mL
Mass of object = 58g
Unknown:
The volume the object must have to be able to float in water = ?
Solution:
To solve this problem, we know that the object must have density value equal to that of water or less than that of water to be able to float.
We then set its density to that of water;
Density =
Volume =
So;
Volume =
= 58mL