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saveliy_v [14]
3 years ago
14

Use the table to determine the charge of phosphate in K3PO4.

Chemistry
1 answer:
sveta [45]3 years ago
3 0

Answer:

                    Charge on Phosphate is -3 (PO₄³⁻)

Explanation:

                     Ions or polyatomic ions are formed when an atom or molecule loses or gains electron(s) respectively.

Example:

              Formation of ions.

                           Na  →  Na⁺  +  e⁻ (Na loses one electron)

                           Cl₂  +  2 e⁻  →  2 Cl⁻ (Cl gains electron)

In polyatomic ions a charge is present on a molecule which has either two or more atoms.

Example:

               CO₃²⁻ , SO₄⁻ , NH₄⁺ e.t.c.

In statement the  K₃PO₄ polyatomic ionic compound. It is made up of three K⁺ ions and one Phosphate ion (PO₄ˣ⁻) ion.

As we know K belongs to group 1 metals so it has one valence electron and thus, forms a cation of +1 charge. So, for a neutral polyatomic ionic compound the overall charge on K₃PO₄ should be zero. Hence,

                                         K (3) + PO₄ (X)  =  0

Or,

                                         +3 + X = 0

Or,

                                         X  =  0 - 3

                                         X  =  -3

Therefore, the charge on phosphate is -3.

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in an experiment 3.425g of lead oxide was reduced to form 3.105g of lead the empirical formula of the lead oxide is?​
Romashka-Z-Leto [24]

Answer:

Pb3O4

Explanation:

According to this question, 3.425g of lead oxide was reduced to form 3.105g of lead in an experiment. Since lead oxide contains both lead (Pb) and oxygen (O) element,

Mass of lead oxide = 3.425g

Mass of lead = 3.105g

Mass of oxygen = (3.425g - 3.105g) = 0.320g

Next, we convert each mass value to mole by dividing by respective molar mass

Pb = 3.105g ÷ 207.2 = 0.0149mol

O = 0.320g ÷ 16 = 0.02mol

Next, we divide each mole value by the smallest (0.0149)

Pb = 0.0149mol ÷ 0.0149mol = 1

O = 0.02mol ÷ 0.0149mol = 1.342

Multiply each ratio value by 3 to get:

Pb = 1 × 3 = 3

O = 1.342 × 3 = 4.026

The whole number ratio, approximately, of Pb and O is 3:4, hence, their empirical formula is Pb3O4.

4 0
2 years ago
Calculate e°cell for a silver-aluminum cell in which the cell reaction is al(s) + 3ag+(aq) → al3+(aq) + 3ag(s) –2.46 v 0.86 v –0
tekilochka [14]
When E° cell is an electrochemical cell which comprises of two half cells.
 
So,

when we have the balanced equation of this half cell :

Al3+(aq) + 3e- → Al(s)   and E°1 = -1.66 V 

and we have  also this balanced equation of this half cell :

Ag+(aq)  + e- → Ag(s)  and E°2 = 0.8 V 

so, we can get E° in Al(s) + 3Ag (aq) → Al3+(aq) + 3Ag(s)

when E° = E°2 - E°1

∴E° =0.8 - (-1.66)

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∴ the correct answer is 2.46 V




6 0
3 years ago
Describe how to find the area of a triangle (do not just give the formula)
NemiM [27]
When you have the bottom measurement of the triangle (base) and the height of the triangle in the center, you multiply them together and then divide by 2.

~Do you need more explaining~?

8 0
3 years ago
A tissue that has the ability to contract is
bonufazy [111]
Muscle tissue

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8 0
3 years ago
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Need a bit of help with this. Fill in the coefficients, explain your answer.
sp2606 [1]

Answer:

4Fe + 3O₂ → 2Fe₂O₃

General Formulas and Concepts:

<u>Chemistry - Reactions</u>

  • Balancing Reactions

Explanation:

<u>Step 1: Define</u>

RxN:   Fe + O₂ → Fe₂O₃

<u>Step 2: Balance</u>

We need to balance both Fe and O.

LCM of 2 and 3 is 6:

Fe + 3O₂ → 2Fe₂O₃

We now need the same amount of Fe on both sides:

4Fe + 3O₂ → 2Fe₂O₃

4 0
3 years ago
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