When a gas is heated,

Chemistry

1 answer:

Nuetrik [128]2 years ago

6 0

Answer: when gas is heated ,they gain more kinetic energy causing them to move faster.

Explanation: so as they gain kinetic energy they hit the walls of the container with more force thus causing pressure to increase

HOPE THIS HELPSS comment if u need more explanation

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What is the change in temperature when 75 grams of water releases -2657 J of energy? The specific heat of water is 4.18 J/g°C

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I think the answer for this is 4702.5 J/g*k Depending on if it is water as a solid liquid or gas. I used water as a liquid when I solved it. J=(75g)(4.18 J/g*k)(15K)

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3.-4.

creativ13 [48]

The power for the first tank is 2kW and the second tank is 150 kw for the theoretical pumping power lifts a solution with a density of 1200 kg/m³ from a tank to a reservoir.

<h3>What is power?</h3>

Power is the amount of energy in kilowatt which is required to do some work that needs energy known as power it is the multiplication of pressure and the flow of liquid.

Power for the tank = pressure of water × flow of water

Substituting the value,

power = 1 × 2 = 2 kW = P1

power = 10 × 15 = 150 kW = P2

Therefore, a solution with a density of 1200 kg/m³ from a tank to a reservoir power for the first tank is 2kW and for the second tank is 150 kW for the theoretical pumping power lifts.

Learn more about power, here:

brainly.com/question/24091709

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1 year ago

A gas vessel is charged with a mixture of pcl3(g) and cl2(g), which is allowed to equilibrate at 450 k. at equilibrium the parti

VikaD [51]

Answer is: Kp = 66,586.
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Kp - equilibrium constants expressed in terms of partial pressures of gases.
Kp = p(PCl₅) ÷ p(PCl₃) · p(Cl₂). p-partial pressure.
Kp = 1,67 atm ÷ 0,132 atm · 0,190 atm
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2 years ago

Why are sulphur and oxygen in group 6 in terms of electronic configuration

Irina-Kira [14]

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3 years ago

What is the mole fraction, X, of solute and the molality, m (or b), for an aqueous solution that is 15.0% NaOH by mass?

GalinKa [24]

Hello!

a) The mole fraction of solute of a 15% NaOH aqueous solution can be calculated in the following way:

First, we have to assume that we have 100 grams of solution. This will simplify the calculations.

Now, we know that this solution has 15 grams of NaOH and 85 grams of water. We can calculate the number of moles of each one in the following way:

$molesNaOH= 15 g NaOH*\frac{1molNaOH}{39,997 g NaOH}=0,3750 moles NaOH \\ \\ moles H_2O=85 gH_2O* \frac{1 mol H_2O}{18 g H_2O}=4,7222 moles H_2O$

To finish, we calculate the mole fraction by dividing the moles of NaOH between the total moles:

$X_{NaOH}= \frac{moles NaOH}{total moles}= \frac{0,3750 moles NaOH}{0,3750 moles NaOH+4,7222 molesH_2O} =0,073$

So, the mole fraction of NaOH is 0,073

b) The molality (moles NaOH/ kg of solvent) of a 15% NaOH aqueous solution can be calculated in the following way:

First, we have to assume that we have 100 grams of solution. This will simplify the calculations.

Now, we know that this solution has 15 grams of NaOH and 85 grams (0,085 kg) of water. We can calculate the moles of NaOH in the following way:

$molesNaOH= 15 g NaOH*\frac{1molNaOH}{39,997 g NaOH}=0,3750 moles NaOH$

Now, we apply the definition of molality to calculate the molality of the solution:

$mNaOH= \frac{moles NaOH}{kg_{solvent}}= \frac{0,3750 moles NaOH}{0,085 kg H_2O}=4,41 m$

So, the molality of this solution is 4,41 m

Have a nice day!

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3 years ago