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babymother [125]
2 years ago
8

(p÷q)

atex-formula">
=(q÷p)
2 - x


​
Mathematics
1 answer:
ryzh [129]2 years ago
5 0

Answer:

Step-by-step explanation:

Hello,

\dfrac{p}{q}*\dfrac{q}{p}=1=(2x+2)(2-x)\\\\ 4x-2x^2+4-2x=1\\\\ -2x^2+2x+4-1=0\\\\ -2x^2+2x+3=0\\\\

There are two solutions

\Delta=b^2-4ac=2^2+4*2*3=4+24=28=7*4\\x_1=\dfrac{-2+\sqrt{7*4}}{-4}=\dfrac{-2+2\sqrt{7}}{-4}=\dfrac{1-\sqrt{7}}{2}\\x_2=\dfrac{1+\sqrt{7}}{2}\\

Hope this helps

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Pls help me with this:((​
BlackZzzverrR [31]

Answer:

9. A. One - to - One Correspondence

10. D. None of the above

5 0
2 years ago
Read 2 more answers
A company recently downsized its number of employees by 30​%. If there are still 70 ​employees, how many employees were there pr
wolverine [178]
Hello there! Given there are 70 employees after downsizing by 30%, let x equal the number of employees prior to the layoffs:

70 would have to be 70% of x.

To find what 70 is 70% of, we can multiply by 100 because 100 is the base denominator:

70 • 100 = 7,000

Given this equation, we can now divide our result by 70 to get what the amount of employees before the layoffs is:

7,000 divided by 70 gives us 100.

x = 100

Now, we can plug our answer in to see if it makes sense.

Does 70/100 represent 70%?

Yes, it does. 70/100 reduces to 7/10, and by adding 3/10 to our 70%, we get the initial amount of employees.

Your final answer: There were 100 employees prior to the layoffs. If you have any extra questions, let me know and I will gladly assist you.
7 0
1 year ago
X-y=2<br>x² -7y² = 2<br>decide the system​
olya-2409 [2.1K]
Wish I can help my g
7 0
2 years ago
Simplify the expression. Rewrite using only positive exponents.
ivanzaharov [21]

The simplification form of the provided expression is x¹⁸a³b³ option

(d) x¹⁸a³b³ is correct.

<h3>What is an integer exponent?</h3>

In mathematics, integer exponents are exponents that should be integers. It may be a positive or negative number. In this situation, the positive integer exponents determine the number of times the base number should be multiplied by itself.

It is given that:

The expression:

= \rm (\dfrac{x^4a^2b^3}{x^{-2}ab^2})^3

After using the integer exponent property:

\rm =\dfrac{x^{12}a^6b^9x^6}{a^3b^6}

= a³b³x¹⁸ Or

=x¹⁸a³b³

Thus, the simplification form of the provided expression is x¹⁸a³b³ option

(d) x¹⁸a³b³ is correct.

Learn more about the integer exponent here:

brainly.com/question/4533599

#SPJ1

4 0
2 years ago
Please help!
larisa [96]
Answer: 
Choice A
1/17; no, they are dependent events

============================================

Explanation:

There are 13 spades and 52 cards total. So 13/52 = 1/4 is the probability of drawing one spade

If we do not replace the card we pull out, then the probability of another spade is 12/51 since there are 12 spades left out of 51 total. 

Multiply the fractions 1/4 and 12/51 to get
(1/4)*(12/51) = (1*12)/(4*51) = 12/204 = 1/17

The two events are not independent because the second event (pulling out a second spade) depends entirely on what happens in the first event (pulling out a first spade). The fact that the probability is altered indicates we have dependent events.

6 0
3 years ago
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