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Nikitich [7]
3 years ago
12

The drain in your 45-gallon bathtub is partially clogged, but you need to take a shower. The showerhead had a flow rate of 2.25

gallons per minute, but the bathtub only drains at a rate of -0.5 gallons per minute. What is the longest shower you can take? ​
Mathematics
2 answers:
sleet_krkn [62]3 years ago
4 0

Answer:

25 minutes 42 seconds

Step-by-step explanation:

The tub will fill at the rate of ...

 2.25 gal/min - 0.50 gal/min = 1.75 gal/min

It will take ...

 45 gal/(1.75 gal/min) ≈ 25.714 min

for the tub to fill.

You can shower for about 25 minutes 42 seconds.

Step-by-step explanation:

Vladimir [108]3 years ago
3 0

Answer:

  25 minutes 42 seconds

Step-by-step explanation:

The tub will fill at the rate of ...

  2.25 gal/min - 0.50 gal/min = 1.75 gal/min

It will take ...

  45 gal/(1.75 gal/min) ≈ 25.714 min

for the tub to fill.

You can shower for about 25 minutes 42 seconds.

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What is the value of y in this system of equations: 3x + y = 9 y = –4x + 10 ?
Ahat [919]
<span>3x + y = 9 (I)
</span><span>y = –4x + 10 (II)
------------------------
</span>\left \{ {{3x + y = 9 } \atop {y = -4x + 10 }} \right.

Pass the incognito "4x" to the first term, changing the signal when changing sides.
<span>-------------------------
simplify by (-1)
</span>\left \{ {{3x + y = 9.(-1)} \atop {4x + y = 10 }} \right.<span>

-------------------------
</span>\left \{ {{- 3x - \diagup\!\!\!\!y =-9} \atop {4x + \diagup\!\!\!\!y = 10}} \right.     &#10;
<span>
-------------------------
</span>\left \{ {{- 3x = - 9} \atop {4x = 10}} \right.<span>

-----------
</span>\boxed{x = 1}<span><span>

</span></span><span>Substitute in equation (I) to find the value of "Y".

</span>3x + y = 9 (I)
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\boxed{y = 6}

Answer:
\boxed{\boxed{ \left \ {{x=1} \atop {y=6}} \right. }}

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The correct answer would be: 4.6 x 10^5

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Answer:

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Step-by-step explanation:

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