Answer:
start at -2 then go right
Step-by-step explanation:
then leave a arrow mark me brainiest.
<span>Answers:
(12x^2 + 3x + 6) + (-7x^2 – 4x – 2) = 5x^2 - x + 4
(2x2 – x) + (-x – 2x2 – 2) = -2x - 2
(x3 + x2 + 2) + (x2 – 2 – x3) = 2x^2
(x2 + x) + (x2 + 8x – 2) = 2x^2 + 9x - 2
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Answer:
So you first count how much times the numbers go up,then you add the number you get it is 6+ you add them with 13 and you get 19.
Step-by-step explanation:
So you first count how much times the numbers go up,then you add the numbers so 1 is not enough 2 is not enough 3 is not enough 4 is not enough 5 is not enough 6 is enough, so we add the six with the number that we are adding which is 13,then you get 19
3.5 miles / 1.25 hours = 2.8 mph
The minimum distance will be along a perpendicular line to the river that passes through the point (7,5)
4x+3y=12
3y=-4x+12
y=-4x/3+12/3
So a line perpendicular to the bank will be:
y=3x/4+b, and we need it to pass through (7,5) so
5=3(7)/4+b
5=21/4+b
20/4-21/4=b
-1/4=b so the perpendicular line is:
y=3x/4-1/4
So now we want to know the point where this perpendicular line meets with the river bank. When it does y=y so we can say:
(3x-1)/4=(-4x+12)/3 cross multiply
3(3x-1)=4(-4x+12)
9x-3=-16x+48
25x=51
x=51/25
x=2.04
y=(3x-1)/4
y=(3*2.04-1)/4
y=1.28
So now that we know the point on the river that is closest to Avery we can calculate his distance from that point...
d^2=(x2-x1)^2+(y2-y1)^2
d^2=(7-2.04)^2+(5-1.28)^2
d^2=38.44
d=√38.44
d=6.2 units
Since he can run at 10 uph...
t=d/v
t=6.2/10
t=0.62 hours (37 min 12 sec)
So it will take him 0.62 hours or 37 minutes and 12 seconds for him to reach the river.
