Answer:
To factor something out you've got to divide, so you would take 5x+40 and divide it all by 5
So, 5x/5= 1x
And, 40/5= 8
Your answer is now x+8 when factored
Answer:
Option B: 
Step-by-step explanation:
The parabola has its concavity downwards, so we need a function in the model:

With a negative value of 'a'
The vertex is (0,0), so we have that:


The x-coordinate of the vertex is given by the equation:



So we have a function in the model:

With a < 0
The only option with this format is B:

Answer:
48, since the numbers are next to each other with no sign, they need to be multiplied, and a negative times a negative is a positive
Step-by-step explanation:
hope this helps
Answer:
A) Suppose we have an onedimensional situation.
in the 0 of our x-axis, we have a fruit tree, and we want to rest at a distance no bigger than 6 ft of the tree, then all the possible positions of our resting place are:
x ∈(-6ft, 6ft)
we can write this as: IxI < 6ft
b) now we think the opposite situation, we want to rest at least 6ft away from the tree, then we have that:
x ∉ [-6ft, 6ft].
or IxI > 6ft.
So you can see that the difference in those two cases is if we want to be "inside a given range" (for the first case) or "outside a given range" (for the second case).
Answer:
Step-by-step explanation:
Given that:
sample size n = 36
standard deviation = 10.1
level of significance ∝ = 0.10
The null hypothesis and the alternative hypothesis can be computed as follows:


The test statistics can be computed as follows:





degree of freedom = n - 1 = 36 - 1 = 35
Since this test is two tailed .
The P -value can be determined by using the EXCEL FUNCTION ( = 2 × CHIDIST(35.7035, 35)
P - value = 2 × 0.435163515
P - value = 0.8703 ( to four decimal places)
Decision Rule : To reject the null hypothesis if P - value is less than the 0.10
Conclusion: We fail to reject null hypothesis ( accept null hypothesis) since p-value is greater than 0.10 and we conclude that there is sufficient claim that the normal range of pulse rates of adults given as 60 to 100 beats per minute resulted to a standard deviation of 10 beats per minute.