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MArishka [77]
3 years ago
13

Round 24.99 to the nearest tenth

Mathematics
1 answer:
klasskru [66]3 years ago
5 0
A tenth of 24.99 would be the first 9 after the point. In order to round it to the nearest tenth, we must look at the number after it. If that number is 5 or above, we must make the tenth one higher. In this case, the number after the tenth is above 5, so we change the tenth to a 1! Now the number becomes 25.00
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Graph the function y = |1.6x – 2| – 3.2. Over which interval is the function increasing?
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You are to graph   <span>y = |1.6x – 2| – 3.2.  I trust you know that the graph of y=|x| is v-shaped, opening up, with vertex at (0,0).

Let's rewrite </span><span>y = |1.6x – 2| – 3.2 by factoring 1.6 out of  |1.6x - 2|:

                     </span><span>y = 1.6*|x – 2/1.6| – 3.2

This tells us that the vertex of   </span><span>y = |1.6x – 2| – 3.2   is at (2/1.6,  -3.2).  If you need an explanation of why this is, please ask.

Plot the vertex at (1.25, -3.2).
Find the y-intercept:  Let x = 0 in  </span><span>y = |1.6x – 2| – 3.2 and find y:

                                                      y = 2-3.2 = -1.2

The y-intercept is located at 0, -1.2)

Plot this y-intercept.

Now draw a straight line from the vertex to this y-intercept.  Reflect that line across the y-axis to obtain the other half of the graph.</span>
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Miguel asked Sandra to make 90 cookies for his party. Sandra needs ¼ cup of sugar to make 15 cookies. She incorrectly calculated
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Step-by-step explanation:

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Step-by-step explanation:

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The function d(s) = 0.0056s squared + 0.14s models the stopping distance
victus00 [196]

Answer:

The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

Step-by-step explanation:

Let be d(s) = 0.0056\cdot s^{2} + 0.14\cdot s, where d is the stopping distance measured in metres and s is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.

The procedure to find the speed related to the given stopping distance is described below:

1) Construct the graph of d(s).

2) Add the function d = 7\,m.

3) The point of intersection between both curves contains the speed related to given stopping distance.

In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

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