Answer:
By writing an experiment report
Explanation:
Answer:
0.1593 L.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and P are constant, and have two different values of V and T:
<em>P₁V₁T₂ = P₂V₂T₁</em>
<em></em>
P₁ = 600 torr/760 = 0.789 atm, V₁ = 185.0 mL = 0.185 L, T₁ = 25.0°C + 273 = 298.0 K.
P₂ (at STP) = 1.0 atm, V₂ = ??? L, T₂ (at STP = 0.0°C) = 0.0°C + 273 = 273.0 K.
<em>∴ V₂ = P₁V₁T₂/P₂T₁</em> = (0.789 atm)(0.185 mL)(298.0 K)/(1.0 atm)(273.0 K) = <em>0.1593 L.</em>
Answer: 2.36 grams
Explanation: One molecule of NaCl has an atomic mass of 58.4 amu. That consists of one atom each of sodium (23 amu) and chlorine (35.4 amu).
Na 23 (23/58.4) = 0.3934
<u>Cl 35.4</u> (35.4/58.4) = 0.6066
58.4 amu
For Na: (6 grams)*(0.3934) = 2.36 grams
Answer:
Option C
Explanation:
No. of Molecules=(Given Weight/Molar weight)*Avagadro No.
Given weight of H2O=3.01g
Molar weight of H2O=18g
On applying the formula, we get:
No. of Molecules=(3.01/18)*6.023*10²³=1.01*10²³