Answer : The half life of 28-Mg in hours is, 6.94
Explanation :
First we have to calculate the rate constant.
Expression for rate law for first order kinetics is given by:

where,
k = rate constant
t = time passed by the sample = 48.0 hr
a = initial amount of the reactant disintegrate = 53500
a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520
Now put all the given values in above equation, we get


Now we have to calculate the half-life.



Therefore, the half life of 28-Mg in hours is, 6.94
Answer:
0.045 L or 45 mL
Explanation:
Moles = Mass/M.Mass
Moles = 10 g / 109.94 g/mol
Moles = 0.09 moles
Also,
Molarity = Moles / Vol in L
Or,
Vol in L = Moles / Molarity
Vol in L = 0.09 mol / 2 mol/L
Vol in L = 0.045 L
X is always the independent variable
Answer:
true
Explanation:
we have many sattelites that are seen by many astounouts in space by telescope but more than half space is not discoverd