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Furkat [3]
4 years ago
10

a scuba diver's tank contains 0.29g of oxygen compressed into volume of 2.3L. What is the pressure in the tank at 9C?

Chemistry
1 answer:
viva [34]4 years ago
5 0

Answer:

The answer to your question is P = 0.18 atm

Explanation:

Data

mass of O₂ = 0.29 g

Volume = 2.3 l

Pressure = ?

Temperature = 9°C

constant of ideal gases = 0.082 atm l/mol°K

Process

1.- Convert the mass of O₂ to moles

                16 g of O₂ -------------------- 1 mol

                0.29 g of O₂ ----------------   x

                    x = (0.29 x 1)/16

                    x = 0.29/16

                    x = 0.018 moles

2.- Convert the temperature to °K

Temperature = 9 + 273 = 282°K

3.- Use the ideal gas law ro find the answer

              PV = nRT

-Solve for P

              P = nRT/V

-Substitution

              P = (0.018 x 0.082 x 282) / 2.3

-Simplification

              P = 0.416/2.3

-Result

               P = 0.18 atm

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3 years ago
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kipiarov [429]

The correct options are these:

1. It will follow the law of conservation of mass.

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3 years ago
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A gas is confined in a 0.3m diameter cylinder by a piston, on which rests a weight. The mass of the piston is 85 kg. The local a
iris [78.8K]

Explanation:

Force applied on the gas will be as follows.

                   F_{gas} = F_{atm} + (m + M) g

As,   F = pressure × area. Hence, calculate the forces as follows.

                  F_{gas} = pressure × area

                         = 1.4 \times 10^{5} Pa \times \pi \times (\frac{0.3}{2})^{2}

                          = 1.979 \times 10^{4} N

                  F_{atm} = pressure × area

                            = 1.0133 \times 10^{5} \times \pi \times (\frac{0.3}{2})^{2}

                            = 1.432 \times 10^{4} N

      F_{gas} - F_{atm} = 5.47 \times 10^{3} N

Substituting the calculated values into the above formula as follows.

                F_{gas} = F_{atm} + (m + M) g

              F_{gas} - F_{atm} = (m + M) g

              5.47 \times 10^{3} N = (m + 85) \times 9.8    

              5.47 \times 10^{3} N = 9.8m + 833

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5 0
4 years ago
If a certain gas occupies a volume of 10. L when the applied pressure is 5.0 atm , find the pressure when the gas occupies a vol
lorasvet [3.4K]

Answer:

20L is the new volume

Explanation:

In this case, moles and T° from the gas remain constant. This is the formula we must apply, to solve this:

P₁ . V₁ = P₂ . V₂

5 atm . 10 L = P₂ . 2.5L

P₂ = (5 atm . 10 L) / 2.5L →20L

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