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d G = 2 (dG NOCl) - 2 (dG NO)
= 2 * 66.08 - 2 * 87.6 = -43.04 kJ /mol
dG = - 2.303 RT log K
-43.04 = - 2.303 RT log K
7.54 = log K
K = 3.42 * 10^7
Kp = k (RT)^dn
d n = 2 - 1 -2 = -1
Kp = (3.42 * 10^7) (8.314 * 298)^-1
Kp = 1.31 * 10^4
The solution needed is prepared as below
by use of the M1V1 =M2 V2 formula where
M1 = 2.25 L
v2 = 1.0M
M2 = 9.0 M
V2 =? l
make V2 the subject of the formula V2 =M1V1/M2
= 2.25 L x 1.0M/9.0 M = 0. 25 L
therefore the solution need 0.25 L of 9.0M H3PO4 and dilute it a final volume of 2.25 l
