Answer:
A. Ba(NO₃)₂(aq) + Na₂CO₃(aq)
Explanation:
- The reaction between aqueous Ba(NO₃)₂ and Na₂CO₃ is a precipitation reaction.
- The complete equation for the reaction is;
Ba(NO₃)₂(aq) + Na₂CO₃(aq) → BaCO₃(s) + NaNO₃(aq)
- Barium carbonate is the precipitate formed during the reaction.
- All nitrates are soluble in water and all salts of sodium are soluble in water, therefore, Ba(NO₃)₂, Na₂CO3, and NaNO₃ are soluble in water.
- Precipitation reaction involves reaction of soluble salts to form a precipitate as one of the product.
Since it is in period five, any element that has a higher atomic number than it could be an answer, therefore, silver, bismuth, and osmium are possibilities.
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Answer: has a double bond
Explanation: O2 has a double bond in its normal form. That is O=O. There are no unpaired electrons in this case are there since there are 2 lone pairs on each oxygen.
The fourth period, or fourth row, of the periodic table contains the elements from Z = 19 (potassium) to Z = 36 (kripton).
The abbreviated electron configuratin of potassium is K = [Ar] 4s.
Where [Ar] is 1s2 2s2 2p6 3s2 3p6.
The next element, Calcium, Z = 20, has electron configuration Ca = [Ar] 4s2.
Starting the next element, Scandium, Z = 21, the atoms start to fill the 3d orbitals. Scandium has electron configuration Sc = [Ar] 4s2 3d.
The 3d orbitals permit to accomodate 10 electrons. So, the filling of 3d orbitals end with the element Z = 30, wich is zinc. The electron configuration of zinc is Zn =[Ar] 4s2 3d10.
So, starting with the element Z = 31 (gallium) until Z = 36, this is 6 elements, will fill the 4p orbitals.Those are Ga, Ge, As, Se, Br and Kr.
The answer is that six elements in the fourth period of the periodic table have one or more 4p electrons. You can find those elements in the right side of the period and are from 13 group to 18 group.
