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2 years ago

Cu + O2 --Cu2O

Chemistry

1 answer:

aniked [119]2 years ago

7 0

Answer:

a. 4Cu + O₂ → 2Cu₂O

b. 266g Cu

c. 102g Cu₂O

Explanation:

Based on the balanced reaction:

a. 4Cu + O₂ → 2Cu₂O

4 moles of Cu reacts per mole of oxygen to produce 2 moles of Cu₂O.

b. To solve this question we need to find the moles of Cu₂O. With these moles and the balanced reaction we can find the moles of Cu and its mass:

Moles Cu₂O -Molar mass: 143.09g/mol-

300g Cu₂O * (1mol / 143.09g) = 2.097 moles Cu₂O

Moles Cu:

2.097 moles Cu₂O * (4mol Cu / 2mol Cu₂O) 4.193 moles Cu

Mass Cu - Molar mass: 63.546g/mol-

4.193 moles Cu * (63.546g / mol) = 266g Cu

c. In the same way, using PV = nRT we can find the moles of Oxygen. With the moles of oxygen we can find the moles of Cu₂O and its mass:

n = PV / RT

P = 1atm at STP, V = 8.0L, R = 0.082atmL/molK, T = 273.15K at STP:

n = 1atm*8.0L / 0.082atmL/molK*273.15K

n = 0.357 moles O₂

Moles Cu₂O:

0.357 moles O₂ * (2mol Cu₂O / 1mol O₂) = 0.714 moles Cu₂O

Mass Cu₂O -Molar mass: 143.09g/mol-

0.714 moles Cu₂O * (143.09g/mol) =

102g Cu₂O

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Answer:

the correct option would be:

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Since the carbohydrate load is an increase in glycogen reserves as an energy source accompanied by a decrease in muscle demand. This is often used in high-performance activities, where strict competencies are required.

Although today some professionals do not support that, but rather support a diet with carbohydrates and proteins.

Explanation:

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3 years ago

Please help ASAP!!!

alisha [4.7K]

Answer:

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2 years ago

What is the ph of a 0.027 M KOH solution?

Monica [59]

First you calculate the concentration of [OH⁻] in solution :

POH = - log [ OH⁻]

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3 years ago

In the laboratory, a student dilutes 18. 9 ml of a 10. 0 m perchloric acid solution to a total volume of 250. 0 ml. what is the

Sever21 [200]

The concentration of diluted solution is 0.756M.

From the question given above, the following data were obtained:

Volume of stock solution (V1) = 18.9 mL

Molarity of stock solution (M1) = 10 M

Volume of diluted solution (V2) = 250 mL

Molarity of diluted solution (M2) =?

We can obtain the molarity of the diluted solution by using the dilution formula as shown follow:

M1V1 = M2V2

10 × 18.9 = M2 ×250

189 = M2 × 250

Divide both side by 100

M2 = 189 / 250

M2 = 0.756 M

Therefore, the molarity of the diluted solution is 0.756 M.

Thus the concluded that concentration of the dilute acid is 0.756 M.

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1 year ago

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masya89 [10]

Answer:

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CH4 + 2O2 → CO2 + 2H2O + 212,800 cal

These reactions are exothermic reaction because heat is evolved.

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The type of reactions in which energy is absorbed are called endothermic reactions.

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it can be written as,

C + H₂O + 131 kj/mol → CO + H₂

Exothermic reaction:

The type of reactions in which energy is released are called exothermic reactions.

In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.

For example:

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C + O₂ → CO₂

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it can be written as,

C + O₂ → CO₂ + 393 Kj/mol

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3 years ago