Answer:
a. 4Cu + O₂ → 2Cu₂O
b. 266g Cu
c. 102g Cu₂O
Explanation:
Based on the balanced reaction:
a. 4Cu + O₂ → 2Cu₂O
<em>4 moles of Cu reacts per mole of oxygen to produce 2 moles of Cu₂O.</em>
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b. To solve this question we need to find the moles of Cu₂O. With these moles and the balanced reaction we can find the moles of Cu and its mass:
<em>Moles Cu₂O -Molar mass: 143.09g/mol-</em>
300g Cu₂O * (1mol / 143.09g) = 2.097 moles Cu₂O
<em>Moles Cu:</em>
2.097 moles Cu₂O * (4mol Cu / 2mol Cu₂O) 4.193 moles Cu
<em>Mass Cu - Molar mass: 63.546g/mol-</em>
4.193 moles Cu * (63.546g / mol) = 266g Cu
c. In the same way, using PV = nRT we can find the moles of Oxygen. With the moles of oxygen we can find the moles of Cu₂O and its mass:
n = PV / RT
P = 1atm at STP, V = 8.0L, R = 0.082atmL/molK, T = 273.15K at STP:
n = 1atm*8.0L / 0.082atmL/molK*273.15K
n = 0.357 moles O₂
<em>Moles Cu₂O:</em>
0.357 moles O₂ * (2mol Cu₂O / 1mol O₂) = 0.714 moles Cu₂O
<em>Mass Cu₂O -Molar mass: 143.09g/mol-</em>
0.714 moles Cu₂O * (143.09g/mol) =
102g Cu₂O
