Answer:
A rhombus and a square since a square is also a rhombus.
Answer:
x3squared-3x2squared-18x
Step-by-step explanation:
1 Expand by distributing terms.
({x}^{2}-6x)(x+3)(x
2
−6x)(x+3)
2 Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd(a+b)(c+d)=ac+ad+bc+bd.
{x}^{3}+3{x}^{2}-6{x}^{2}-18xx
3
+3x
2
−6x
2
−18x
3 Collect like terms.
{x}^{3}+(3{x}^{2}-6{x}^{2})-18xx
3
+(3x
2
−6x
2
)−18x
4 Simplify.
{x}^{3}-3{x}^{2}-18xx
3
−3x
2
−18x
Answer:
Dina's friend is jealous of Dina's confidence so she wanted to "what up" her :)
Step-by-step explanation:
*Given
Money of Phoebe - 3 times as much as Andy
Money of Andy - 2 times as much as Polly
Total money of Phoebe, - <span>£270
</span> Andy and Polly
*Solution
Let
B - Phoebe's money
A - Andy's money
L - Polly's money
1. The money of the Phoebe, Andy, and Polly, when added together would total <span>£270. Thus,
</span>
B + A + L = <span>£270 (EQUATION 1)
2. Phoebe has three times as much money as Andy and this is expressed as
B = 3A
3. Andy has twice as much money as Polly and this is expressed as
A = 2L</span> (EQUATION 2)
<span>
4. This means that Phoebe has ____ as much money as Polly,
B = 3A
B = 3 x (2L)
B = 6L </span>(EQUATION 3)<span>
This step allows us to eliminate the variables B and A in EQUATION 1 by expressing the equation in terms of Polly's money only.
5. Substituting B with 6L, and A with 2L, EQUATION 1 becomes,
6L + 2L + L = </span><span>£270
</span> 9L = <span>£270
</span> L = <span>£30
So, Polly has </span><span>£30.
6. Substituting L into EQUATIONS 2 and 3 would give us the values for Andy's money and Phoebe's money, respectively.
</span>
A = 2L
A = 2(£30)
A = £60
Andy has £60
B = 6L
B = 6(£30)
B = £180
Phoebe has £180
Therefore, Polly's money is £30, Andy's is £60, and Phoebe's is £180.
Answer:
D
Step-by-step explanation:
firstly,y-intercept, x=0,A and b wrong
sub x=0
0.25⁰=1
(0,1)
D
