This is the diffiarence of two perfect squares. this should be memorised, but if not here it is
a^2-b^2=(a-b)(a+b)
so 16^2-81=16^2-9^2
so the answer is (16-9)(16+9)
Answer:
parallel
Step-by-step explanation:
4-2/-9-0= 2/-9
6-8/4+5= -2/9
Hey there!
We can solve systems two ways - substitution and elimination. It seems in this case that elimination is going to be easier.
Let's begin by multiplying the top equation by 3, and the bottom equation by 4:
3(5x - 4y = -24)
15x - 12y = -72
4(4x + 3y = 18)
16x + 12y = 72
Next, we'll add the two equations together to get rid of, or eliminate, the y variable and solve for the x variable:
(15x - 12y = -72) + (16x + 12y = 72)
31x = 0
x = 0
Next, we'll plug the value of the x variable into the top equation and solve for the y variable:
5(0) - 4y = -24
-4y = -24
y = 6
Therefore, x = 0 and y = 6.
Hope this helps!! :)
Answer:
$20
Step-by-step explanation:
I = 400(.05)(1)
I = 20
