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Korvikt [17]
3 years ago
9

maria exercises for 2 3/8 hours every saturday. she runs for 2/7 of the time. how much time does she spend running

Mathematics
1 answer:
Margaret [11]3 years ago
6 0
Uhhmmmm I'm not sure. I'm sorry.. :(
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What would the number, 4 tens + 3 + eight hundred thousand + 5000 look like?
qwelly [4]
805043 would be the answer i believe
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3 years ago
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What is the area of a rectangle with a width of x2 + x + 1 and a length of<br> 3x2 - 2x - 1?
nata0808 [166]

Answer:

x^{4} + 3x³ - 3x - 1

Step-by-step explanation:

The area (A) of a rectangle is calculated as

A = lw ( l is the length and w the width ) , thus

A = (3x² - 2x - 1)(x² + x + 1)

Each term in the second factor is multiplied by each term in the first factor, then

A = 3x²(x² + x + 1) - 2x(x² + x + 1) - 1(x² + x + 1) ← distribute parenthesis

   = 3x^{4} + 3x³ + 3x² - 2x^{4} - 2x² - 2x - x² - x - 1 ← collect like terms

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7 0
3 years ago
What is the perimeter of the figure in the diagram (round to three decimal places if necessary)?
Y_Kistochka [10]
Perimeter (p) = length around a shape.
So any horizontal sides we can add based upon their length in x-values and any vertical sides we can add based upon their length in y-values. The diagonal sides we can find by the distance formula:
d =  \sqrt{( {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} }
So the bottom base goes from x=1 to x=8, then up 1, right 1, and up from y=3 to y=9, then left from x=9 to x=6, down from y=9 to y=6, left from x=6 to x=3.
So far that is: (8-1)+1+1+(9-3)+(9-6)+(9-6)+(6-3)
= 7+2+6+3+3+3 = 24
Now for the diagonal:
d =  \sqrt{( {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2}) }  \\  =  \sqrt{( {(3- 1)}^{2}  +  {(6 - 2)}^{2} )}  \\  =  \sqrt{( {2}^{2}  +  {4}^{2} )}  =  \sqrt{(4 + 16)} \\  =  \sqrt{20} = 2 \sqrt{5}  = 4.47
P = 24 + 4.47 = 28.47
D) 28.472

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3 years ago
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Evaluate b-2a-c for a = -7, b = 3, and c = -7 <br><br> a: 3<br> b: -18 <br> c: 24
fomenos

c

Step-by-step explanation:

jdhdjejrbrbbrbrjdjejdjjshsh

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A bed is 6 1/2 long. the material to make a sheet for the bed is to be 1 3/4 times as long to allowed for hems and tucking under
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The piece of material needed would be 11.375 units long

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