For this case we must solve the following quadratic equation:

Where:

The solution is given by:

Substituting:

Thus, we have two roots:

ANswer:

Let start off with 5/8+7/8= 1 4/8
Now it's 13+1 4/8= 14 4/8 or 14 1/2 :)
Use the FOLD method<span>
(a+b)(c+d)=ac+ad+bc+bd
</span><span>−12<span>s<span><span>^2 </span><span></span></span></span>+ 3st + 8ts − 2<span>t<span><span>^2</span><span>
</span></span></span></span>Collect like terms
-12{s}^{2}+(3st+8st)-2{t}^{2}
Simplify
<span>-12{s}^{2}+11st-2{t}^{2}<span>−12<span>s<span><span>2</span><span></span></span></span>+11st−2<span>t<span><span>2
The answer is = -12s^2 + 11st - 2t^2</span></span></span></span></span>
Step-by-step explanation:
(x, y) -> (x+3, y+4)
that is what 3 units to the right (3 units into the outsource x direction) and 4 units up (4 units into the posits y directing) mean.
so, all points go through this translation
(1, 7) -> (4, 11)
(-4, -2) -> (-1, 2)
(-3, 5) -> (0, 9)
Answer:
The percentage of the bag that should have popped 96 kernels or more is 2.1%.
Step-by-step explanation:
The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.
The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.
Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.
Compute the probability that a bag popped 96 kernels or more as follows:
Apply continuity correction:


*Use a <em>z</em>-table.
The probability that a bag popped 96 kernels or more is 0.021.
The percentage is, 0.021 × 100 = 2.1%.
Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.