It would seem the problem requires you compute the mean, median, and standard deviation of each of the data sets. This is nicely done using the statistics functions of your graphing calculator.
Data Set A (mean, median, standard deviation) = (29.7, 29.5, √12.71)
Data Set B (mean, median, standard deviation) = (27.95, 27, √6.1475)
1. False. Data Set B is skewed to the right.
2. TRUE. 27.95 is within 3 of 29.7.
3. False. √12.71 ≠ √6.1475
4. False. The mean of Data Set A is 29.7.
5. False. Data Set A has the higher standard deviation.
6. TRUE. 29.7 is close to 29.5.
The true statements are
• the 2nd one
• the 6th one
Answer:
A right triangle
Step-by-step explanation:
It's where the altitudes all intersect. In a right triangle, the legs of the right triangle are the altitudes-- especially evident when the right angle is at the base. The altitude from the hypotenuse to the right angle also passes through the right angle.
Let's say Ronnie is thinking of X.
If 2(x) = x+5, we would first distribute the 2.
2x = x+5
We would then need to isolate the variable. We would do so by getting all variables to one side. The easier choice would be to subtract x from both sides.
2x=x+5
-1x -1x
This becomes
x=5
Ronnie is thinking of the number five.
5•2=10 and 5+5=10.
<h3>
Answer: 17</h3>
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Explanation:
We'll start things off by computing the inner function u(2)
Plug x = 2 into the u(x) function
u(x) = -x-1
u(2) = -2-1
u(2) = -3
This tells us that w(u(2)) is the same as w(-3). I replaced u(2) with -3.
We'll plug x = -3 into the w(x) function
w(x) = 2x^2-1
w(-3) = 2(-3)^2 - 1
w(-3) = 2(9) - 1
w(-3) = 18-1
w(-3) = 17
Therefore, w(u(2)) = 17
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Here's a slightly different approach:
Let's find what w(u(x)) is in general
w(x) = 2x^2 - 1
w(u(x)) = 2(u(x))^2 - 1
w(u(x)) = 2(-x-1)^2 - 1
Then we can plug in x = 2
w(u(x)) = 2(-x-1)^2 - 1
w(u(2)) = 2(-2-1)^2 - 1
w(u(2)) = 2(-3)^2 - 1
w(u(2)) = 2(9) - 1
w(u(2)) = 18 - 1
w(u(2)) = 17
Answer:
4.4166666667 or 4.417
Step-by-step explanation:
7÷12-5=4.4166666667 or 4.417
