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forsale [732]
3 years ago
10

In a Scrabble tournament, the scores were normally distributed and the mean score was 420.2 points with a standard deviation of

105.0 points. What is the probability that the score of a randomly selected competitor differs from the mean score by less than 50 points
Mathematics
1 answer:
sveta [45]3 years ago
5 0

Answer:

P(370.2

And we can find this probability with this difference:

P(-0.762

Step-by-step explanation:

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(420.2,105)  

Where \mu=420.2 and \sigma=105

We are interested on this probability

P(X

And we can use the z score formula given by:

z=\frac{x-\mu}{\sigma}

And replacing we got:

P(370.2

And we can find this probability with this difference:

P(-0.762

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Ganezh [65]

Answer:

Jamie's claims are correct because 3/10 of the spool twine is left over after using 1/2 of the spool twin for friendship knot

Step-by-step explanation:

Full question: He claims to have 3/10 of the original spool of twine leftover.

First, we compare 3/10 with 4/5 - 1/2

The lowest common multiple for2 and 5 is 10.

To write 4/5 as a fraction with common denominator, multiply numerator and denominator by 2

4/5 = (4×2)/(5×2) = 8/10

To write 1/2 as a fraction with a common denominator, multiply denominator and numerator by5

1/2 =(1×5)/(2×5) = 5/0

So we have :

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Since denominators are equal ,we go ahead and subtract

8/10 - 5/10 = (8-5)/10 = 3/10

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Answer:

this is correct on edge

Step-by-step explanation:

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