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Alex73 [517]
2 years ago
11

The table below shows the educational attainment of a country's population, aged 25 and over. Use the data in the table, express

ed in millions to find the probability that a randomly selected citizenaged 25 or over , was a man with 4 years of college (or more)

Mathematics
1 answer:
Aloiza [94]2 years ago
3 0

Answer:

The answer is "\bold{\frac{22}{171}}"

Step-by-step explanation:

There are 22 million males that have completed four years of undergraduate, according to the data below: (or more). This is predicated on a population of 171 million.

The chances we're searching about \frac{(22\ million)}{(171\ million)} = \frac{22}{171}

however

This proportion could be further reduced because 22 and 171 have no common features (other than 1).

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12 divided by 22 is a repeating decimal

12 ÷ 22 = 0.545454......

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How to determine whether to move right or left on the number line when adding rational numbers?
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3 years ago
Ahhhh help everyone help me solve this ....​
vovangra [49]

Answer:

y =  \frac{18 {w}^{2}  {x}^{2}  {z}^{2} }{25}

Step-by-step explanation:

\frac{3wx}{ \sqrt{2y} }  =  \frac{5}{2z}  \\  \\  \sqrt{2y}  \times 5 = 3wx \times 2z \\  \\  \sqrt{2y}   \times 5 = 6wxz \\  \\  \sqrt{2y}  =  \frac{6wxz}{5}  \\  \\  {( \sqrt{2y} })^{2}  =  {( \frac{6wxz}{5} })^{2}  \\  \\ 2y =  \frac{36 {w}^{2} {x}^{2} {z}^{2}   }{25}  \\  \\  \\  y =  \frac{36 {w}^{2} {x}^{2}  {z}^{2}  }{25}  \div 2 \\  \\  \\ y =  \frac{36 {w}^{2} {x}^{2} {z}^{2}   }{25}  \times  \frac{1}{2}  \\  \\  \\ y =  \frac{36 {w}^{2} {x}^{2}  {z}^{2}  }{50}  \\  \\  \\ y =  \frac{18 {w}^{2} {x}^{2}   {z}^{2} }{25}

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2 years ago
What is the simplified form of 12z^2-7z-12/3z^2+2z-8? ...?
gavmur [86]
It should go like this:

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(4z +3) / (z + 2)
4 0
3 years ago
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