The corresponding segments MN and PO in the image are parallel.<span />
Answer:
Step-by-step explanation:
it is D
The equation which can be used to find the number of quarters and nickels is; n + q = 84, 0.05n + 0.25q = 17.80.
<h3>Quarters and nickels</h3>
- Total coins = 84
- Total value = $17.80
let
- Number of quarters = q
- Number of nickels = n
n + q = 84
0.05n + 0.25q = 17.80
From equation (1)
n = 84 - q
Substitute into (2)
0.05n + 0.25q = 17.80
0.05(84 - q) + 0.25q = 17.80
4.2 - 0.05q + 0.25q = 17.80
- 0.05q + 0.25q = 17.80 - 4.2
0.20q = 13.60
q = 13.60 / 0.20
q = 68
Substitute q = 68 into
n + q = 84
n + 68 = 84
n = 84 - 68
n = 16
Therefore, the number of quarters and nickels are 68 and 16 respectively.
Learn more about quarters and nickels:
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Answer:
<h2>2/3</h2>
Step-by-step explanation:
This problem bothers on probability
Given that two dice are expected to give an outcome of sum greater than 8
But in the problem statement the first die is already settled since it is showing 6 already.
Now for the second die, the possible outcomes that will add up with the first die to produce a figure greater than 8 are (3,4,5,6)
The probability of obtaining either of these numbers is 4/6= 2/3
<em>Having the first die settled, this means that the probability of obtaining a sum of 8 is 2/3</em>
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