First isolate the group with h in it
minus 2pir^2 from both sides
s-2pir^2=2pirh
divide both sides by 2pir
(s-2pir^2)/(2pir)=h
Answer:
x intercepts -sqrt(5), + sqrt(5)
y intercept -5
Step-by-step explanation:
y = x^2 -5
to find the x intercept set y=0 and solve for x
0 = x^2-5
add 5 to each side
5 = x^2
take the square root of each side
+- sqrt(5) = sqrt(x^2)
x = +-sqrt(5) there are 2 x intercepts since it is a quadratic
to find the y intercept set x=0 and solve for y
y = 0-5
y = -5
Answer:
Write a cosine equation with the following properties: Amplitude: 3. Period: 2pi. Midline: 2. Phase shift: 4 units shifted left. In the form of: y=a cos b(x-h) +k.
To find f(g(x)), plug g(x) into f(x) and simplify.
f(x/2) = 2 - 1/(x/2)
All you have to do is simplify the right side of the equation.
Take it from here.
