All categories

4 years ago

WILL MARK BRAINLIEST!

Physics

2 answers:

Vlad1618 [11]4 years ago

7 0

B.Shape of continents look like puzzle pieces that can fit into one another

elena55 [62]4 years ago

4 0

Alfred Wegener's hypothesis was that all the continents had once been joined together in a single landmass and have since drifted apart.
So, the answer is A

You might be interested in

Based on the tug of war pictured below, what is the net force? –190 N 10 N –10 N 190 N.

umka21 [38]

Force is defined as the push or pull applied to the body. Its unit is Newton. The net force will be 10 N on the right side.

What is force?

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

The given data in the problem is;

F₁ is forced by person 1 = 100 N

F₂ is forced by person 2= 90 N

Fₓ is the net force

Fₓ = F₁ -F₂

Fₓ = 100-90

Fₓ= 10 N

Hence the net force will be 10 N on the right side.

To learn more about the force refer to the link;

brainly.com/question/26115859

7 0

3 years ago

Explain the difference between a fuse and a circuit breaker if you were designing a circuit for a reading lamp would you include

sesenic [268]

The answer is Fuse. Circuit breakers and fuses are generally known as "Overload Protection Devices. The difference between a fuse and a circuit breaker is that a fuse is a one time circuit element while a circuit breaker is a multiple use device. If you were designing a circuit for a reading lamp, a fuse would do. Since almost all household installed a circuit breaker for outlets, etc,

7 0

3 years ago

Two in-phase loudspeakers emit identical 1000 Hz sound waves along the x-axis. Part A What distance should one speaker be placed

Fiesta28 [93]

The distance a speaker should be placed behind other sound to have an amplitude 1.50 times is 4.523 m.

<h3>What is wavelength?</h3>

The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.

Wavelength λ = v/f

Two in-phase loudspeakers emit identical 1000 Hz sound waves along the x-axis.

λ = 343 m/s /1000 Hz

λ = 0.343 m

Distance, one should speaker be placed behind the other for the sound to have an amplitude 1.50 times that of each speaker alone.

The amplitude of the waveform due to waves,

A = 2a cos (ΔΦ/2)

ΔΦ = 2π x Δx/λ

So, A = 2a cos (π x Δx/λ)

Substitute the values, we get

1.5a = 2a cos (3.14 x Δx/ 0.343)

Δx = 4.523 m

Thus, the distance is 4.523 m.

Learn more about wavelength.

brainly.com/question/13533093

#SPJ1

7 0

2 years ago

Consider two planets of mass m and 2m,

Rzqust [24]

Answer:

Part a)

$\frac{F_1}{F_2} = 10.125$

Part b)

$\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12$

Part c)

$\frac{T_1}{T_2} = 9.54$

Explanation:

Part a)

As we know that the gravitational force is given as

$F = \frac{GMm}{r^2}$

so we will have to find the ratio of force on two planets due to star

so here we have

$\frac{F_1}{F_2} = \frac{m_1r_2^2}{m_2r_1^2}$

$\frac{F_1}{F_2} = \frac{m (4.5r)^2}{(2m) r}$

$\frac{F_1}{F_2} = 10.125$

Part b)

Orbital speed is given as

$v = \sqrt{\frac{GM}{r}}$

so the ratio of two orbital speed is given as

$\frac{v_1}{v_2} = \frac{r_2}{r_1}$

$\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12$

Part c)

Time period is given as

$T = 2\pi\sqrt{\frac{r^3}{GM}}$

so the ratio of two time period is given as

$\frac{T_1}{T_2} = \sqrt{\frac{r_1^3}{r_2^3}}$

$\frac{T_1}{T_2} = \sqrt{\frac{4.5r^3}{r^3}}$

$\frac{T_1}{T_2} = 9.54$

8 0

3 years ago

Read 2 more answers

What change in entropy occurs when a 0.15 kg ice cube at -18 °C is transformed into steam at 120 °c 4.

Studentka2010 [4]

Answer: The change in entropy of the given process is 1324.8 J/K

Explanation:

The processes involved in the given problem are:

$1.)H_2O(s)(-18^oC,255K)\rightarrow H_2O(s)(0^oC,273K)\\2.)H_2O(s)(0^oC,273K)\rightarrow H_2O(l)(0^oC,273K)\\3.)H_2O(l)(0^oC,273K)\rightarrow H_2O(l)(100^oC,373K)\\4.)H_2O(l)(100^oC,373K)\rightarrow H_2O(g)(100^oC,373K)\\5.)H_2O(g)(100^oC,373K)\rightarrow H_2O(g)(120^oC,393K)$