Answer:
The mass of the box, m = 30.61 Kg
The acceleration of the box, a = 0.65 m/s²
Explanation:
Given that,
The weight of the box, w = 300 N
The sliding force acting on the box, F = 20
Since the weight of a body is equal to the product of mass and displacement. The mass of the box is given by the relation
m = w/g
Substituting the given values in the above equation
m = 300 / 9.8
= 30.81 Kg
Hence, the weight of the box is, w = 30.81 Kg
Since the sliding force acting on the box is 20 N
Therefore, acceleration
a = F / m
= 20 / 0.81
= 0.65 m/s²
Hence, the acceleration acting on the box, a = 0.65 m/s²
Answer:
10 m/s
Explanation:
Momentum before collision = momentum after collision
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(8 kg)(8 m/s) + (6 kg)(6 m/s) = (8 kg)(5 m/s) + (6 kg) v
64 kg m/s + 36 kg m/s = 40 kg m/s + (6 kg) v
60 kg m/s = (6 kg) v
v = 10 m/s
I think it's d......... Good luck