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igomit [66]
3 years ago
11

They don't have an Astronomy Section and I believe that this falls the closest to Physics

Physics
1 answer:
Ksenya-84 [330]3 years ago
5 0
The only thing we know of so far that can shift light to longer wavelengths is the "Doppler" effect. If the source and the observer are moving apart, then the observer sees wavelengths that are longer than they should be. If the source and the observer are moving toward each other, then the observer sees wavelengths that are shorter than they should be. It works for ANY wave ... sound, light, water etc. The trick is to know what the wavelength SHOULD be. If you know that, then you can tell whether you and the source are moving together or apart, and you can even tell how fast. If the lines in a star"s spectrum are at wavelengths that are too long, then from everything we know right now, the star and Earth are moving apart.
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Given a force of 90 N and a acceleration of 30 m/s/s, what is the object’s mass?
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A Newton is the amount of force applied to a 1 kg object that will cause it to have an acceleration of 1 m/s2.
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A stunt pilot in an air show performs a loop-the-loop in a vertical circle of radius 3.80 103 m. During this performance the pil
mr Goodwill [35]

The apparent weight of the pilot would be 619.48 N and the speed he would experience at weightlessness is 192. 97 m/s

<h3>What is apparent weight?</h3>

Apparent weight is a property of object that co-relates to the heaviness of the object.

It differs from the weight of an object as a result of the in-balance between the force acting on the object and an equal but opposite force

<h3>How to calculate the apparent weight</h3>

Formula:

Apparent weight = Real weight (mg) - m v∧2 ÷ r

Where m = mass

g = acceleration due to gravity = 9.8 m/s²

v = constant velocity = 2. 10 × 10∧2 m/s

r = radius = 3.80 × 10∧3 m

Note that weight = mg

m = weight ÷ g = 623 ÷ 9.8 = 63. 57 kg

a. Apparent wieight = 623 - (63. 57 × 2.10 × 10∧2 × 2.10 × 10∧2) ÷ 3.80 × 10∧3)

= 623 - (63.57 × 210) ÷ 3800

= 623 - 13377 ÷ 3800

= 623 - 3. 52

= 619.48 N

b. At weightless, weight = 0

Speed, V = √g× r = √ 9.8 × 3800 = √37,240 = 192. 97 m/s

Hence, The apparent weight of the pilot would be 619.48 N and the speed he would experience at weightlessness is 192. 97 m/s

Read more on apparent weight here:

brainly.com/question/11180653

#SPJ1

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2 years ago
The areas of the continents that are under shallow water are
Sunny_sXe [5.5K]

Answer:

costal areas

Explanation:

4 0
3 years ago
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