Two particles, with identical positive charges and a separation of 2.85 x 10⁻² m, are released from rest. Immediately after the
release, particle 1 has an acceleration vector a₁ whose magnitude is 4.50 x 10³ m/s², while particle 2 has an acceleration vector a₂ whose magnitude is 8.15 x 10³ m/s². Particle 1 has a mass of 6.40 10⁻⁶ kg.
Find
(a) the charge on each particle _______ C and
(b) the mass of particle 2. ________ kg
Find
(a) the charge on each particle _______ C and
(b) the mass of particle 2. ________ kg
1 answer:
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Answer:
The magnitude of the vector A is <u>51 m.</u>
Explanation:
Given:
The horizontal component of a vector A is given as:
The vertical component of a vector A is given as:
Now, we know that, a vector A can be resolved into two mutually perpendicular components; one along the x axis and the other along the y axis. The magnitude of the vector A can be written as the square root of the sum of the squares of each component.
Therefore, the magnitude of vector A is given as:
Now, plug in 44.4 for , 25.1 for
and solve for the magnitude of A. This gives,
Therefore, the magnitude of the vector A is 51 m.