The proper time between two events is measured by clocks at rest in a reference frame in which the two events: The proper time b
2 answers:
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The position of the object at time t =2.0 s is <u>6.4 m.</u>
Velocity vₓ of a body is the rate at which the position x of the object changes with time.
Therefore,
Write an equation for x.
Substitute the equation for vₓ =2t² in the integral.
Here, the constant of integration is C and it is determined by applying initial conditions.
When t =0, x = 1. 1m
Substitute 2.0s for t.
The position of the particle at t =2.0 s is <u>6.4m</u>
Answer:
6 m/s
Explanation:
Given that :
mass of the block m = 200.0 g = 200 × 10⁻³ kg
the horizontal spring constant k = 4500.0 N/m
position of the block (distance x) = 4.00 cm = 0.04 m
To determine the speed the block will be traveling when it leaves the spring; we applying the work done on the spring as it is stretched (or compressed) with the kinetic energy.
i.e
v = 6 m/s
Hence,the speed the block will be traveling when it leaves the spring is 6 m/s