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Mnenie [13.5K]
2 years ago
8

The proper time between two events is measured by clocks at rest in a reference frame in which the two events: The proper time b

etween two events is measured by clocks at rest in a reference frame in which the two events:
a. are separated by the distance a light signal can travel during the time interval
b. occur at the same time
c. satisfy none of the above
d. occur in Nashville occur at the same coordinates
Physics
2 answers:
alekssr [168]2 years ago
8 0

Answer:

a - As long as the time between 2 events is reconcilable with a light signal, the time between the events, in that frame, can be determined.

Lemur [1.5K]2 years ago
8 0
The proper time between true events as measured by car
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PART ONE
Helga [31]

Answer:

1.129×10⁻⁵ N

1.295 m

Explanation:

Take right to be positive.  Sum of forces on the 31.8 kg mass:

∑F = GM₁m / r₁² − GM₂m / r₂²

∑F = G (M₁ − M₂) m / r²

∑F = (6.672×10⁻¹¹ N kg²/m²) (516 kg − 207 kg) (31.8 kg) / (0.482 m / 2)²

∑F = 1.129×10⁻⁵ N

Repeating the same steps, but this time ∑F = 0 and we're solving for r.

∑F = GM₁m / r₁² − GM₂m / r₂²

0 = GM₁m / r₁² − GM₂m / r₂²

GM₁m / r₁² = GM₂m / r₂²

M₁ / r₁² = M₂ / r₂²

516 / r² = 207 / (0.482 − r)²

516 (0.482 − r)² = 207 r²

516 (0.232 − 0.964 r + r²) = 207 r²

119.9 − 497.4 r + 516 r² = 207 r²

119.9 − 497.4 r + 309 r² = 0

r = 0.295 or 1.315

r can't be greater than 0.482, so r = 0.295 m.

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3 years ago
1+5-(-5 - 1) whats the answer​
vladimir2022 [97]

Answer:

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6 0
2 years ago
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Advocard [28]

Answer:

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2 years ago
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scoundrel [369]

<span>6.67 metros por segundo
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</span>
Espero que esto te ayude:)
5 0
3 years ago
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