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3 years ago

I need 5 & 6 answered. just don’t look at my answers because they’re wrong.

Mathematics

1 answer:

inn [45]3 years ago

4 0

U have posted 6 & 7 instead so let me answer them instead ..as for 6 you must use Pythagoras theorem ..

Lib _ _ _ P. So u can see they form a right angled triangle. by pythagoras ,answer would be 4 .

Similarly draw a rough diagram for 2nd one u will get the answer as √495 foot ..

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Answer:

2.5 pounds of Granny Smith apples.

Step-by-step explanation:

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3 years ago

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Write in slope-intercept form an equation of the line that passes through the points (−5,−9) and (5,1).

o-na [289]

Answer:

y=x-4

Step-by-step explanation:

The slope is given by

m = (y2-y1)/(x2-x1)

m = (1--9)/(5--5)

m = (1+9)/(5+5)

= 10/10

= 1

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We have the slope and a point,so we can use point slope form

y-y1 = m(x-x1)

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y-1 = x-5

Add 1 to each side

y-1+1 = x-5+1

y=x-4

This is slope intercept form (y= mx+b)

3 0

3 years ago

11. Which regular polygon has a minimum rotation of 45° to carry the polygon onto itself?

ASHA 777 [7]

Answer:

the answer is a octagon that has rotation of 45degrees

3 0

3 years ago

Help with 33 and 34 please!!!

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33. 15x10=150x9
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3 0

3 years ago

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A geometric sequence is shown below.

mestny [16]

Answer:

An explicit representation for the nth term of the sequence:

$f_n=-\frac{1}{2}\cdot \:4^{n-1}$

It means, option (B) should be true.

Step-by-step explanation:

Given the geometric sequence

$-\frac{1}{2},\:-2,\:-8,\:-32,...$

A geometric sequence has a constant ratio, denoted by 'r', and is defined by

$f_n=f_1\cdot r^{n-1}$

Determining the common ratios of all the adjacent terms

$\frac{-2}{-\frac{1}{2}}=4,\:\quad \frac{-8}{-2}=4,\:\quad \frac{-32}{-8}=4$

As the ratio is the same, so

r = 4

Given that f₁ = -1/2

substituting r = 4, and f₁ = -1/2 in the nth term

$f_n=f_1\cdot r^{n-1}$

$f_n=-\frac{1}{2}\cdot \:4^{n-1}$

Thus, an explicit representation for the nth term of the sequence:

$f_n=-\frac{1}{2}\cdot \:4^{n-1}$

It means, option (B) should be true.

8 0

2 years ago