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3 years ago

Are the ratios 11:9 and 2:1 equivalent? yes or no

Mathematics

2 answers:

tresset_1 [31]3 years ago

7 0

Answer:

yes

Step-by-step explanation:

vampirchik [111]3 years ago

3 0

Answer:

Step-by-step explanation:

We can determine if they are equivalent if the cross products are equal

11 2

----- = ------

9 1

11*1 = 2*9

11 = 18

This is false so the ratios are not equivalent

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NEED ANSWER ASAP

kkurt [141]

Answer:

$f(2) = 81$

$g(2) = 83$

Science class had a higher average

Step-by-step explanation:

Given

$f(x) = 0.5x + 80$

g(x) table

Solving (a): f(2)

We have:

$f(x) = 0.5x + 80$

So:

$f(2) = 0.5*2 + 80$

$f(2) = 1 + 80$

$f(2) = 81$

Solving (b): g(2)

From the given table.

$g(2) = 83$

Solving (c): f(4) or g(4); which is greater

$f(x) = 0.5x + 80$

So:

$f(4) = 0.5*4+80$

$f(4) = 2+80$

$f(4) = 82$

For g(4): Notice that in the table of g(x); g(x) increases by 2 when x increases by 1

This means that:

$g(x) = g(x-1)+2$

$g(4) = g(4-1)+2:$

$g(4) = g(3)+2$

$g(4) = 85+2$

$g(4) = 87$

Hence, g(4) i.e. Science class is greater

6 0

3 years ago

Is 9.4 rational or irrational :p, please help

densk [106]

Answer:

i think its rational.

Step-by-step explanation:

7 0

3 years ago

List the angles in triangle QRS from smallest to largest.

schepotkina [342]

Answer:

angle R

Step-by-step explanation:

To solve this we will use cosine rule

Cosine rule

cos(A) = $\frac{b^{2}+c^{2}-a^{2}}{2bc}$

suppose,

q = 6.25

s = 11.04

r = 13.19

angleQ = $cos^{-1}(\frac{13.19^{2}+11.04^{2}-6.52^{2}}{2(13.19)(11.04)})$

= 30.58

angleR = $cos^{-1}(\frac{6.52^{2}+11.04^{2}-13.19^{2}}{2(6.52)(11.04)})$

= 93.82

angleS = $cos^{-1}(\frac{6.52^{2}+13.19^{2}-11.04^{2}}{2(6.52)(13.19)})$

= 56.63

4 0

3 years ago

Help on number 8 please!

solmaris [256]

Answer:

ab/3

Step-by-step explanation:

I don't really know how to explain.

Μα†hway

hope this helps!

5 0

2 years ago

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Solve the equation 4m = 28 for m. A. 3 B. 4 C. 5 D. 7

Paha777 [63]

D 28/4=7 that is the answer for the question

3 0

3 years ago

Read 2 more answers