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Sladkaya [172]
3 years ago
5

Help? Fraction? Triangle similarity.

7D%20" id="TexFormula1" title=" \frac{62}{15.5} x \frac{92}{x} " alt=" \frac{62}{15.5} x \frac{92}{x} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Over [174]3 years ago
8 0
62 / 15.5  = 92 /  x

to find x cross multiply:-

62x = 15.5 * 92
x =  (15.5*92) / 62
  = 23
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If Trent has 11 quarters and dimes in his pocket, and they have a combined value of 200 cents, how many of each coin does he hav
allsm [11]

Answer:

Trent has 6 quarters and 5 dimes.

Step-by-step explanation:

Consider the provided information.

Let q =  Number of quarters

d = Number of dimes.

Trent has 11 quarters and dimes.

q+d=11

q=11-d

The worth of a quarter is 25 cents.

The worth of a dimes is 10 cents

25q+10d=200

Substitute the value of q in above equation.

25(11-d)+10d=200

275-25d+10d=200

15d=75  

d=5  

Substitute the value of d in q=11-d

q=11-5

q=6

Hence, Trent has 6 quarters and 5 dimes.

4 0
3 years ago
Which expression is equivalent to 5(2x+3)-2x?
IrinaK [193]

Answer:

x= -15/8

Step-by-step explanation:

5(2x+3)-2x = 0

10x+15-2x = 0

8x= -15

x= -15/8

3 0
3 years ago
Read 2 more answers
Add the two expressions <br> -4.2x+3 and 2.5x-6<br><br><br> please help me with this
dalvyx [7]

-1.7×-6 is the answer. Hope this helps.

6 0
3 years ago
Read 2 more answers
4 mm
Schach [20]

Answer:

Area  =  40mm

Example:

The below-solved example problem may be useful to understand how the values are being used in the mathematical formulas to find the trapezoid area.

Example Problem :

Find the area of a trapezoid having the bottom length a = 15 cm, top length b = 12 & height h = 9 cm?

Solution :

The given values

bottom length a = 15 cm

top length b = 12 cm

height h = 10 cm

Step by step calculation

formula to find area = ((a + b)/2) h

substitute the values

= ((15 + 12)/2) x 9

= 121.5 cm2

7 0
3 years ago
I need help please I will give you brainliest
liubo4ka [24]

Answer:

Step-by-step explanation:

4a: x=729

4b: x=9/25

5a ln (2)

5b log2(24

7 0
3 years ago
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