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Anastaziya [24]
4 years ago
6

With a certain tail wind a jet aircraft arrives at its destination, 1,890 miles away, in 3 hours. Flying against the same wind,

the plane makes the return trip in 3 3/8 hours. Find the wind speed and the plane's airspeed.
Mathematics
1 answer:
Gelneren [198K]4 years ago
3 0
<span>Find the wind speed and the plane's airspeed.
:
Let s = speed of the plane in still air
Let w = speed of the wind
then
(s-w) = plane speed against the wind
and
(s+w) = plane speed with the wind
:
Change 3 3/8 hrs to 3.375 hrs
:
The trips there and back are equal distance, (1890 mi) write two distance equations
dist = time * speed
:
3.375(s-w) = 1890
3.0(s + w) = 1890

:
It is convenient that we can simplify both these equations:
divide the 1st by 3.375
divide the 2nd by 3
resulting in two simple equations that can be used for elimination of w
s - w = 560
s + w = 630
----------------adding eliminates w, find s
2s = 1190
s = 
s = 595 mph is the plane speed in still air
Find w
595 + w = 630
w = 630 - 595
w = 35 mph is the wind spee</span>
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Answer:

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Step-by-step explanation:

So, we first name our variables, say, a for number of adult tickets, and c for child tickets.

Then we write our system of equations, first the total $ sale:

5.2c + 8.3a = 1087.10

Then we write the 2nd equation, the total number of tickets:

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Now, we can solve the system:

We do have different methods, let's to by subsitution.

make some change to the 2nd equation, to make c the subject: c = 156 - a

Now we plug that into the 1st equation:

5.2(156 - a) + 8.3a = 1087.10

811.2 - 5.2a + 8.3a = 1087.10

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8 0
3 years ago
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Answer:

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Divide through by 4

2 ≦ n+1 < 6

Subtract 1 for all three sides:

1 ≦ n < 5

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Step-by-step explanation:

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Step-by-step explanation:

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