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Anastaziya [24]
3 years ago
6

With a certain tail wind a jet aircraft arrives at its destination, 1,890 miles away, in 3 hours. Flying against the same wind,

the plane makes the return trip in 3 3/8 hours. Find the wind speed and the plane's airspeed.
Mathematics
1 answer:
Gelneren [198K]3 years ago
3 0
<span>Find the wind speed and the plane's airspeed.
:
Let s = speed of the plane in still air
Let w = speed of the wind
then
(s-w) = plane speed against the wind
and
(s+w) = plane speed with the wind
:
Change 3 3/8 hrs to 3.375 hrs
:
The trips there and back are equal distance, (1890 mi) write two distance equations
dist = time * speed
:
3.375(s-w) = 1890
3.0(s + w) = 1890

:
It is convenient that we can simplify both these equations:
divide the 1st by 3.375
divide the 2nd by 3
resulting in two simple equations that can be used for elimination of w
s - w = 560
s + w = 630
----------------adding eliminates w, find s
2s = 1190
s = 
s = 595 mph is the plane speed in still air
Find w
595 + w = 630
w = 630 - 595
w = 35 mph is the wind spee</span>
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Base 11 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A} where A is treated as a single digit number

Base 12 has the digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B}

Base 13 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C}

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3 years ago
Solve the equation.<br> 5 = -2n<br> n =<br> Pls hurry 20 points
Katarina [22]
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3 0
3 years ago
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Help! Best answer gets brainliest
julsineya [31]

Answer:

7.9

Step-by-step explanation:

the first thing to do is find the second projection.

16-7 = 9

than we can use a proportion to find BD

7 : BD = BD : 9

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we have to use the square root because in the proportion BD Is repeated two times. If we don’t use it, we find BD^2

7 0
3 years ago
During the first decade of the century, the population of a certain city was 145,380 in 2000 and 219,135 in 2010. Find the expon
Likurg_2 [28]

Answer:

The exponential growth function is P=145380e^{0.04103t}

Step-by-step explanation:

Given: The population of a certain city was 145,380 in 2000 and 219,135 in 2010.

To find: exponential growth function that models the growth of the city

Solution:

The exponential growth function is given by P=P_0 e^{kt}

Here, P denotes total population after time t

P_0 denotes initial population

k denotes rate of growth

t denotes time

As P(0)=145,380,

145380=P_0e^{0}\\145380=P_0\\P=145380e^{kt}

As P(10)=219135

219135=145380e^{10k}\\e^{10k}=\frac{219135}{145380}\\=1.507326\\k=\frac{1}{10}\ln (1.507326)\\=0.04103\\\Rightarrow P=145380e^{0.04103t}

8 0
3 years ago
Is (a-3)(2a^2 + 3a + 3) equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)
vovikov84 [41]
<h3>Answer: Yes they are equivalent</h3>

==============================================

Work Shown:

Expand out the first expression to get

(a-3)(2a^2 + 3a + 3)

a(2a^2 + 3a + 3) - 3(2a^2 + 3a + 3)

2a^3 + 3a^2 + 3a - 6a^2 - 9a - 9

2a^3 + (3a^2-6a^2) + (3a-9a) - 9

2a^3 - 3a^2 - 6a - 9

Divide every term by 2 so we can pull out a 2 through the distributive property

2a^3 - 3a^2 - 6a - 9 = 2(a^3 - 1.5a^2 - 3a - 4.5)

This shows that (a-3)(2a^2 + 3a + 3) is equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)

4 0
3 years ago
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