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2 years ago

Help! Best answer gets brainliest

Mathematics

1 answer:

julsineya [31]2 years ago

7 0

Answer:

7.9

Step-by-step explanation:

the first thing to do is find the second projection.

16-7 = 9

than we can use a proportion to find BD

7 : BD = BD : 9

BD = √9 x 7 = √63 = 7.9

we have to use the square root because in the proportion BD Is repeated two times. If we don’t use it, we find BD^2

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The concentration of dichlorodiphenyltrichloroethane (DDT - an infamous pesticide) in Lake Michigan has been declining exponenti

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Answer: A) $y=13e^{-0.1359t}$

B) H = 5.10

C) Yes

Step-by-step explanation: Exponential Decay function is a model that describes the reducing of an amount by a constant rate over time. Generally, it is written in the form: $y(t)=Ce^{rt}$

A) C is initial quantity, in this case, the initial concentration of DDT. To determine r, using the data given:

$y(t)=Ce^{rt}$

$2.22=13e^{13r}$

$e^{13r}=0.1708$

Using a natural logarithm property called power rule:

$13r=ln(0.1708)$

$r=\frac{ln(0.1708)}{13}$

$r=-0.1359$

The decay function for concentration of DDT through the years is $y(t)=13e^{-0.1359t}$

B) The value of H is calculated by $y=C(0.5)^{\frac{t}{H} }$

$2.22=13(0.5)^{\frac{13}{H} }$

$(0.5)^{\frac{13}{H} }=0.1708$

Again, using power rule for logarithm:

$\frac{13}{H} log(0.5)=log(0.1708)$

$\frac{13}{H} =\frac{log(0.1708)}{log(0.5)}$

$\frac{13}{H} =2.55$

H = 5.10

Constant H in the half-life formula is H=5.10

C) Using model $y(t)=13e^{-0.1359t}$ to determine concentration of DDT in 1995:

$y(24)=13e^{-0.1359.24}$

y(24) = 0.5

By 1995, the concentration of DDT is 0.5 ppm, so using this model is possible to reduce such amount and more of DDT.

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2 years ago

| x+4 | = 5 Solve the absolute value equation or indicate that the equation has no solution.

vladimir2022 [97]

| x + 4 | = 5

x + 4 = 5 x + 4 = -5
x = 5 - 4 x = -5 - 4
x = 1 x = -9

solution : x = 1 and x = -9

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