All categories

2 years ago

A square has an area of 81 square inches. What is its perimeter?

Mathematics

2 answers:

Rina8888 [55]2 years ago

8 0

Step-by-step explanation:

In order to find the perimeter we need to find the length first ...

...Here, the area is already given ...

Area = 81 inches square

length = ?

Now....

( The formula of area is l × l )

$area = {l}^{2}$

$81 = {l}^{2}$

Now we should find square root of 81...

$l = \sqrt{81}$

$l \: = 9$

Now we find length so it's easy for us to find perimeter...

The formula of perimeter of square is 4l ..

= 4l

= 4 × 9

= 36 inches

hence the answer is 36 inches....

disa [49]2 years ago

7 0

Area of square = $s^2$ where, $s$ is the side length of the square.

$81=s^2$

$9=s$

s must be positive since it is a side length, so the negative root of 81 is rejected.

Perimeter= $4s$

Perimeter= $4(9)=36inches$

You might be interested in

A sprinkler rotates through an angle of 115° spraying water outward for a distance of 12 ft. find the exact area watered, then r

bekas [8.4K]

The sprinkler rotates through an angle of 115° and sprinkles water outward for a distance of 12 ft.
Therefore the radius of the circular section is 12 ft as shown in the diagram below.

The total circle occupies 360°. Therefore the area watered is
A = (115/360)*π*(12 ft)²
= 144.513 ft²

Answer: 144.5 ft (nearest tenth)

4 0

3 years ago

Find the 89th term of 25,35,45

MAXImum [283]

Answer:

The 89th term would be 895.

Step-by-step explanation:

There is a pattern of adding 10 each time. Notice that the 5 at the end doesn't change and that the first number continues (i.e. 2, 3, 4, 5, 6). All you have to do is add an 89 in front of the 5 and that is your answer, 895.

4 0

3 years ago

Read 2 more answers

126888493 value of the 3 8's

melisa1 [442]

The eights are in the thousands, ten thousands, and hundred thousands:<span>126888493=</span>thousands, 126888493=ten thousands, and 126888493=hundred thousands.

5 0

3 years ago

Read 2 more answers

How to find the area of triangle?

ikadub [295]

Answer:

$(i). \\ { \tt{area = 2(\frac{1}{2} \times base \times height}} )\\ = 4 \times 3 \\ = 12 \: sq \: units \\ \\ (iii). \\ = \frac{1}{2} \times 8 \times 6 \\ = 24 \: sq \: units \\ \\ (ii). \\ = \frac{1}{2} \times 12 \times 5 \\ = 30 \: sq \: units$

5 0

3 years ago

Bet u can’t solve this

S_A_V [24]

Answer:

Step-by-step explanation:

Assuming you're solving for p:

$m=2^{-1} *2^p(2^p-1)$

Let $y=2^p$

Now we can re-write the equation with $y$ instead of $2^p$ .

$m=\frac{1}{2} y(y-1)$

$2m=y^2-y$

$y^2-y-2m=0$

Use the quadratic formula to get:

$y = \frac{1+\sqrt{1+8m} }{2}$

$y = \frac{1-\sqrt{1+8m} }{2}$

Therefore, using natural log and log rules:

$2^p = \frac{1+\sqrt{1+8m} }{2}$ , $ln(2^p)= ln(\frac{1+\sqrt{1+8m} }{2})$ , $pln(2) = ln(\frac{1+\sqrt{1+8m} }{2})$ , $p = \frac{ln(\frac{1+\sqrt{1+8m} }{2})}{ln(2)}$

$2^p = \frac{1-\sqrt{1+8m} }{2}$ , $ln(2^p)= ln(\frac{1-\sqrt{1+8m} }{2})$ , $pln(2) = ln(\frac{1-\sqrt{1+8m} }{2})$ , $p = \frac{ln(\frac{1-\sqrt{1+8m} }{2})}{ln(2)}$

If I haven't made any mistakes this should be correct!

7 0

3 years ago