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2 years ago

Joy is making hand-painted ornaments for

Mathematics

2 answers:

Nutka1998 [239]2 years ago

7 0

Answer:

1 ornament per 3 hours

in 15 hours she will have 7.5 of them done

koban [17]2 years ago

6 0

Answer:

5 Ornaments

Step-by-step explanation:

First, we take into account that 24 hours are in one day. We then make the equation 6/24, which tells us that she can make 8 ornaments in 24 hours. That's not the answer we need though.

We will divide 2 by 6 = 0.33

We can take that and multiply it by 15 hours to get 5 ornaments total.

Hope this answer helped u out :D

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saul85 [17]

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Step-by-step explanation:

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3 years ago

Need help with my sister's homework

masha68 [24]

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3 0

4 years ago

Read 2 more answers

A volleyball player serves the ball from a height of 6.5 feet above the ground with an initial vertical velocity of 21 feet per

Vaselesa [24]

Answer:

Option D. $H(t) = 6.5+21t-16t^2$

Step-by-step explanation:

we know that

If air resistance is ignored, the height h (in feet) of the ball t seconds after it is served is given by

$H(t) = - \frac{1}{2}g t^2 + V_0t + H_0$

where

g is the acceleration due to gravity which on earth is approximately equal to 32 feet / sec^2

V_0 is the initial velocity (when t = 0 )

H_0 is the initial height (when t = 0)

In this problem we have

$V_0=21\ ft/sec\\H_0=6.5\ ft$

substitute the given values

$H(t) = - \frac{1}{2}(32) t^2 + (21)t + 6.5$

$H(t) = -16t^2 + 21t + 6.5$

Rewrite

$H(t) = 6.5+21t-16t^2$

3 0

3 years ago

Help me on this please

zalisa [80]

Answer:

1. (x, y) → (x + 3, y - 2)

Vertices of the image

a) (-2, - 3)

b) (-2, 3)

c) (2, 2)

2. (x, y) → (x - 3, y + 5)

Vertices of the image

a) (-3, 2)

b) (0, 2)

c) (0, 4)

d) (2, 4)

3. (x, y) → (x + 4, y)

Vertices of the image

a) (-1, -2)

b) (1, -2)

c) (3, -2)

4. (x, y) → (x + 6, y + 1)

Vertices of the image

a) (1, -1)

b) (1, -2)

c) (2, -2)

d) (2, -4)

e) (3, -1)

f) (3, -3)

g) (4, -3)

h) (1, -4)

5. (x, y) → (x, y - 4)

Vertices of the image

a) (0, -2)

b) (0, -3)

c) (2, -2)

d) (2, -4)

6. (x, y) → (x - 1, y + 4)

Vertices of the image

a) (-5, 3)

b) (-5, -1)

c) (-3, 0)

d) (-3, -1)

Explanation:

To identify each IMAGE you should perform the following steps:

List the vertex points of the preimage (the original figure) as ordered pairs.

Apply the transformation rule to every point of the preimage

List the image of each vertex after applying each transformation, also as ordered pairs.

1. (x, y) → (x + 3, y - 2)

The rule means that every point of the preimage is translated three units to the right and 2 units down.

Vertices of the preimage Vertices of the image

a) (-5,2) (-5 + 3, -1 - 2) = (-2, - 3)

b) (-5, 5) (-5 + 3, 5 - 2) = (-2, 3)

c) (-1, 4) (-1 + 3, 4 - 2) = (2, 2)

2. (x,y) → (x - 3, y + 5)

The rule means that every point of the preimage is translated three units to the left and five units down.

Vertices of the preimage Vertices of the image

a) (0, -3) (0 - 3, -3 + 5) = (-3, 2)

b) (3, -3) (3 - 3, -3 + 5) = (0, 2)

c) (3, -1) (3 - 3, -1 + 5) = (0, 4)

d) (5, -1) (5 - 3, -1 + 5) = (2, 4)

3. (x, y) → (x + 4, y)

The rule represents a translation 4 units to the right.

Vertices of the preimage Vertices of the image

a) (-5, -2) (-5 + 4, -2) = (-1, -2)

b) (-3, -5) (-3 + 4, -2) = (1, -2)

c) (-1, -2) (-1 + 4, -2) = (3, -2)

4. (x, y) → (x + 6, y + 1)

Vertices of the preimage Vertices of the image

a) (-5, -2) (-5 + 6, -2 + 1) = (1, -1)

b) (-5, -3) (-5 + 6, -3 + 1) = (1, -2)

c) (-4, -3) (-4 + 6, -3 + 1) = (2, -2)

d) (-4, -5) (-4 + 6, -5 + 1) = (2, -4)

e) (-3, -2) (-3 + 6, -2 + 1) = (3, -1)

f) (-3, -4) (-3 + 6, -4 + 1) = (3, -3)

g) (-2, -4) (-2 + 6, -4 + 1) = (4, -3)

h) (-2, -5) (-2 + 3, -5 + 1) = (1, -4)

5. (x, y) → (x, y - 4)

This is a translation four units down

Vertices of the preimage Vertices of the image

a) (0, 2) (0, 2 - 4) = (0, -2)

b) (0,1) (0, 1 - 4) = (0, -3)

c) (2, 2) (2, 2 - 4) = (2, -2)

d) (2,0) (2, 0 - 4) = (2, -4)

6. (x, y) → (x - 1, y + 4)

This is a translation one unit to the left and four units up.

Vertices of the pre-image Vertices of the image

a) (-4, -1) (-4 - 1, -1 + 4) = (-5, 3)

b) (-4 - 5) (-4 - 1, -5 + 4) = (-5, -1)

c) (-2, -4) (- 2 - 1, -4 + 4) = (-3, 0)

d) (-2, -5) (-2 - 1, -5 + 4) = (-3, -1)

8 0

3 years ago

The measure of each interior angle of a regular polygon is 150 how many sides does the polygon have?

Dmitry [639]

The exterior and an interior angles always add up to 180 degrees.
180-150=One exterior angle
180-150=30
We know that all of the exterior angles add up to 360
360/30= the number of sides
360/30=12
The shape has 12 sides.

3 0

3 years ago