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AysviL [449]
3 years ago
8

A Tax Attorney in the Tax department of the law firm ABC represents Mr. X in a matter before the IRS. Another lawyer in the Liti

gation Department of ABC has been approached by Paula to sue Mr. X because she was seriously injured when Mr. X’s dog attacked her. What would the lawyer need to do before taking Paula’s case?
Physics
1 answer:
yanalaym [24]3 years ago
4 0

Answer:

the lawyer should Inform Mr. X through that Tax attorney and ABC management to get approval.

Explanation:

According to my research on different lawyer proceedings, I can say that based on the information provided within the question before taking Paula's Case the lawyer should Inform Mr. X through that Tax attorney and ABC management to get approval. This can be said because since both Mr.X and Paula are clients of the law firm, there may be a breach in confidentiality if the lawyer decides to take Paula's case. Therefore he needs to talk to everyone involved and place restrictions if the case is taken.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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A baseball has a mass of 0.15 kg and radius 3.7 cm. In a baseball game, a pitcher throws the ball with a substantial spin so tha
mylen [45]

Answer:

Rotational kinetic energy = 0.099 J

Translational kinetic energy = 200 J

The moment of inertia of a solid sphere is I = \frac{2}{5}mr^2.

Explanation:

Rotational kinetic energy is given by

\text{RKE} = \frac{1}{2}I\omega^2

where <em>I</em> is the moment of inertia and <em>ω</em> is the angular speed.

For a solid sphere,

I = \frac{2}{5}mr^2

where <em>m</em> is its mass and <em>r</em> is its radius.

From the question,

<em>ω</em> = 49 rad/s

<em>m</em> = 0.15 kg

<em>r</em> = 3.7 cm = 0.037 m

\text{RKE} = \frac{1}{2}\times \frac{2}{5} mr^2\omega^2 = \frac{1}{5} mr^2\omega^2

\text{RKE} = \frac{1}{5} (0.15\ \text{kg})(0.037\ \text{m})^2(49\ \text{rad/s})^2 = 0.099\text{ J}

Translational kinetic energy is given by

\text{TKE} = \frac{1}{2} mv^2

where <em>v</em> is the linear speed.

\text{TKE} = \frac{1}{2} (0.15\ \text{kg})(52\ \text{m/s})^2 = 200\text{ J}

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