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natka813 [3]
3 years ago
9

A 2.00 kg block is placed against a spring on a frictionless 36° incline. the spring, whose spring constant is 19.8n/cm, is com

pressed 22.8 cm and then released. what is the elastic potential energy of the compressed spring?
Physics
1 answer:
alekssr [168]3 years ago
5 0
A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
Read more on Brainly.com - brainly.com/question/1581851#readmore
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A cat walks along a plank with mass M= 7.00 kg. The plank is supported by two sawhorses. The center of mass of the plank is a di
solong [7]

Answer:

Before the plank will tip cat will walk 1.652 m

Explanation:

Mass of the cat along with plank m_1=7kg

Center of mass of the plank d_1=0.850m

Mass of cat m_2=3.6kg

We have to find how far right of sawhorse B.

Plank will tip when weight of the cat about B is greater than the torque by the weight of the plank.

Balancing the the torque

m_1gd_1=m_1gd_2

7\times 9.8\times 0.850=3.6\times 9.8\times d_2

d_2=1.652m

5 0
4 years ago
The speed of light is 3 x 108 m/s (300,000,000 m/s). A light wave has a wavelength of 400 nm (0.0000004 m). What is the frequenc
kirill115 [55]

Explanation:

velocity = wavelength × frequency

3×10⁸ = 400/10⁹ × frequency

frequency = 3 × 10¹⁵ /400

frequency = 75×10¹¹Hz

6 0
2 years ago
What is the unit of G in the F=Gm1m2/r^2​
kobusy [5.1K]


G
has the SI units
m
3
k
g
⋅
s
2
6 0
3 years ago
Read 2 more answers
The moon Phobos orbits Mars
Soloha48 [4]

Answer:

Explanation:

We are basically needing to solve for the time in the equation d = rt, where d is the distance around Mars (aka the circumference), r is the velocity, and t is time. We need to find the circumference and the velocity. We will begin with the velocity.

Because the gravitational attraction between Phobos and Mars provides the centripetal acceleration necessary to keep Phobos in its (sort of) circular path, the equation we use for this is:

F_g=F_c which says that Force supplied by gravity is equal to the centripetal force. Expanding that:

\frac{Gm_{Phobos}m_{Mars}}{r^2}=\frac{m_{Phobos}v^2}{r}

When we move that around mathematically to solve for the velocity value, what we end up with is:

v=\sqrt{\frac{Gm_{Mars}}{r} and filling in:

v=\sqrt{\frac{(6.67*10^{-11})(6.42*10^{23})}{9.38*10^6} } and we get that

v = 2100 m/s

Now for the circumference:

C = 2πr and

C = 2(3.1415)(9.38 × 10⁶) so

C = 5.9 × 10⁷

Putting that all together in the C = vT equation:

5.9 × 10⁷ = 2100T so

T = 2.8 × 10⁴ sec or 7.8 hours

8 0
3 years ago
How is the pressure of a gas related to its concentration of particles?
Nat2105 [25]
Increasing the pressure of gas is like exactly the same as increasing its concentration. If you have a given mass of gas, the way you increase its pressure is to squeeze it into a smaller volume.
Hope this helps!
3 0
3 years ago
Read 2 more answers
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