Destiny can u come comment on this plz

You are shooting at a moving target. you estimate the length of lead necessary to hit the target. you maintain that lead as you

uysha [10]

The answer to this problem is:

This method of shooting is called <u>“sustained lead”.</u>

<span>This method of shooting at moving targets requires a bit of experience. Since the accuracy of hitting the target relies on the estimated amount of lead, this is useful when the path and speed of the target is steady and known.</span>

5 0

3 years ago

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When the lights of an automobile are switched on, an ammeter in series with them reads 12 A and a voltmeter connected across the

Anarel [89]

Answer:

a) Emf of battery = 15.6 V

b) Current through the starting motor = 104 A

Explanation:

The image for the question seem not to be attached but, when the starting motor wasn't connected, the lights are in series with the battery connection and when the starting motor is connected, it is in parallel with the lights.

a) For this part, we use the information when the starting motor isn't connected.

Let the emf of the battery be E = ?

The voltage across the terminals be V = 15 V

Let the internal resistance of the battery be R = 0.05 ohms

And the current in the circuit be I = 12 A

Since the internal resistance is modelled to be in series with the battery, the loop equation for this circuit will be

E = V + IR

E = 15 + (12)(0.05) = 15 + 0.6 = 15.6 V

From this information now, we can obtain the resistance of the lights.

From Ohm's law,

Voltage across the lights = 15 V

Current through the lights = 12 A

Resistance of the lights = R₀

V = IR₀

R₀ = (15/12) = 1.25 ohms

b) Now, the starting motor is connected and the resistance in the circuit is if the form

Internal resistance in series with the parallel combination of resistance of starting motor and the resistance of the lights.

Current through the lights = 8.0 A

Voltage across the lights = IR₀ = 8×1.25 = 10 V.

Since the starting motor is in parallel with the lights, they will have the same voltage across them, that is, 10 V

But the voltage across the internal resistance = (Emf of battery) - (Voltage across the parallel combination of lights and starting motor) = 15.6 - 10 = 5.6 V

Current through the internal resistance = (5.6/0.05) = 112 A

Current through the starting motor = 112 - 8 = 104 A

Hope this Helps!!!

3 0

4 years ago

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Two bicycle tires are set rolling with the same initial speed of 4.0 m/s along a long, straight road, and the distance each trav

umka2103 [35]

Answer:

The coefficient of rolling friction will be "0.011".

Explanation:

The given values are:

Initial speed,

$v_i = 4.0 \ m/s$

then,

$v_f=\frac{4.0}{2}$

$=2.0 \ m/s$

Distance,

s = 18.2 m

The acceleration of a bicycle will be:

⇒ $a=\frac{v_f^2-v_i^2}{2s}$

On substituting the given values, we get

⇒ $=\frac{(2.0)^2-(4.0)^2}{2\times 18.2}$

⇒ $=\frac{4-8}{37}$

⇒ $=\frac{-4}{37}$

⇒ $=0.108 \ m/s^2$

As we know,

⇒ $f=ma$

and,

⇒ $\mu_rmg=ma$

⇒ $\mu_r=\frac{a}{g}$

On substituting the values, we get

⇒ $=\frac{0.108}{9.8}$

⇒ $=0.011$

7 0

3 years ago

Explain Newton's third law in your own words.

Kazeer [188]

Newton's third law states "for every action, there is an equal and opposite reaction."

What this is pretty much saying is that for every action, there is a consequence. One force connects and triggers another.

5 0

3 years ago

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5. Which of these affect the brightness of a bulb? Choose all that apply.* 6 po

schepotkina [342]

Answer:

The voltage of the battery

7 0

3 years ago