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3 years ago

What are limits in algebra

1 answer:

3 0

In mathematics, a limit is the value that a function or sequence "approaches" as the input or index approaches some value.

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(4,-5) (3,5)<br> slope =<br> What is the slope of this equation?

galben [10]

The slope is -10, I used a graph for this.

4 0

3 years ago

Read 2 more answers

1 2 3 4 5 6 7 8 10 Which set of steps will translate f(x) = 67 to g(x) = 67-5-7? Shift f(x) = 6X five units to the left and seve

True [87]

Answer:

Shift f(x) = 6' seven units to the left and five units down.

Step-by-step explanation:

6 0

3 years ago

5/2x-3 is this a monomial, binomial, or trinomial

Serga [27]

Its a binomial. There are two terms

6 0

3 years ago

Find p(-4) and p(2) for the function p(x)=11x^5-11x^4-5x^2+15x-8

egoroff_w [7]

hi,

you must replace x by the number between parenthese.

I show you with the first one and let you do the second one

p(x) = 11x^5 -11x^4 - 5x^2 +15x-8

p(-4) = 11 (-4)^5 - 11 (-4)^4 -5(-4)² +15(-4) -8

p(-4) = 11 ( -1024- 256) - 5*16 -60-8

p(-4) = 11 ( -1280) -80-60-8

p(-4) = - 14080 - 148

p(-4) = - 14 228

7 0

3 years ago

How does the sample size affect the validity of an empirical argument? A. The larger the sample size the better. B. The smaller

astra-53 [7]

Answer:

A. The larger the sample size the better.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In this question:

We have to look at the standard error, which is:

$s = \frac{\sigma}{\sqrt{n}}$

This means that an increase in the sample size reduces the standard error, and thus, the larger the sample size the better, and the correct answer is given by option a.

7 0

3 years ago