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Firlakuza [10]
1 year ago
5

Is g(x)=4+x^2/1+x^4 even, odd or neither

Mathematics
1 answer:
UkoKoshka [18]1 year ago
4 0

Since g(-x) is equal to g(x), the function is an EVEN FUNCTION.

<h3>Is the given function even, odd or neither?</h3>

Given the function in the question;

g(x) = (4 + x²)/(1 + x⁴)

To determine if the function is even, odd or neither, we find g(-x) by substituting -x for all occurrence of x in the function.

g(x) = (4 + x²)/(1 + x⁴)

g(-1) = (4 + (-x)²)/(1 + (-x)⁴)

Simplify

g(-x) = (4 + x²)/(1 + x⁴)

Hence,

g(-x) = g(x)

Since g(-x) is equal to g(x), the function is an EVEN FUNCTION.

Learn more about even functions here: brainly.com/question/23446734

#SPJ1

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Answer this pls..................​
Sindrei [870]

Answer:

so we know:

total of 20 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry has a total of 14 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14

8 students are in physics

1 2 3 4 5 6 7 8

3 are in all of them

1 2 3

1) underline the main 3

total of 20 students

<u>1 2 3 </u>4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry has a total of 14 students

<u>1 2 3</u> 4 5 6 7 8 9 10 11 12 13 14

8 students are in physics

<u>1 2 3 </u>4 5 6 7 8

2) lets bold the physics students, if you are in physics you have to do chem so that means 8 of the chem students also take physics.

total

<u>1 2 3 </u>4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry

<u>1 2 3</u> 4 5 6 7 8 9 10 11 12 13 14

physics

<u>1 2 3 </u>4 5 6 7 8

3) now we bring biology into the "equation"

off the bat we know 3 are definitely in Biology.

so if 4 study ONLY biology we can cross them off our list see the {}

total

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

<u>1 2 3</u> 4 5 6 7 8 {9 10 11 12} 13 14

physics

<u>1 2 3 </u>4 5 6 7 8

biology

<u>1 2 3 </u>

<u />

4) so we have a total of 20 students, 3 in all of the classes <u>(underlined)</u>, 8 in physics (bolded). If there 14 in chemistry, 4 take ONLY chemistry {}, 8 take chemistry as well (bolded), that leaves two students, so they must belong in biology. lets<em> italicise</em> them.

total

<em><u>1 2 3 </u></em>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 16 17 18 19 20

chemistry

<em><u>1 2 3</u></em><em> </em>4 5 6 7 8 {9 10 11 12} <em>13 14</em>

physics

<em><u>1 2 3</u></em><u> </u>4 5 6 7 8

biology

<em><u>1 2 3 </u></em><em> 13 14</em>

<u />

5) out of our total of 20 students we know 14 of the students classes, so the remaining six must be in biology.

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 <em>16 17 18 19 20</em>

chemistry

<u>1 2 3</u> 4 5 6 7 8 {9 10 11 12} <em>13 14</em>

physics

<u>1 2 3 </u>4 5 6 7 8

biology

<u>1 2 3 </u><em>13 14</em> 15 <em>16 17 18 19 20</em>

6) so that was our "diagram" so now lets count how many are in chemistry and biology but NOT physics.

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 <em>16 17 18 19 20</em>

chemistry

<u>-1 2 3</u> 4 5 6 7 8- {9 10 11 12} <em>13 14</em>

physics

<u>-1 2 3 </u>4 5 6 7 8-

biology

<u>-1 2 3 -</u><em>13 14</em> 15 <em>16 17 18 19 20</em>

there are 14 students in chemistry and 11 in biology, 5 of them are in both classes so 14-5= 9 and 11-5= 6 9+6=16. BUT 8 of those sixteen are also in -physics- so we arent counting them, we put those students in dashes. so lets count the students out of the dashes. so<em> twelve</em> of them are in chemistry and biology but not physics.

7) so how many are in just biology but not the other classes? lets look at the graph.

<u>1 2 3 </u>4 5 6 7 8 {9 10 11 12} <em>13 14</em> 15 <em>16 17 18 19 20</em>

chemistry

<u>1 2 3</u> 4 5 6 7 8 {9 10 11 12} <em>13 14</em>

physics

<u>1 2 3 </u>4 5 6 7 8

biology

<u>1 2 3 </u><em>13 14</em> 15 <em>16 17 18 19 20</em>

in the class of biology students 1 2 3 13 and 14 take other classes that leaves students 15 16 17 18 19 and 20. so 6 students take ONLY biology.

sorry its long but i hope this helps!

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