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allochka39001 [22]
3 years ago
14

Question 3 / 5

Mathematics
1 answer:
Allisa [31]3 years ago
7 0

There are 10 seats in ferris wheel of love.

One couple can fit in to one seat. That means 1 couple per seat.

Given, in each minute a seat passes by the entrance or exit stage. That means one couple can use the seat for one minute. That means 1 seat per minute.

The wheel starts functioning at 8 p.m for half an hour. In 1 hour there are 60 minutes. So half an hour means \frac{60}{2} = 30 minutes.

So we have got 1 couple per seat and 1 seat per minute. If we multiply them we will get 1 couple per minute.

We have got in 1 minute there is 1 couple.

So in 30 minutes there are (1)(30) couples = 30 couples.

We have got the required answer here.

There are 30 couples who took a ride in the ferris wheel of love.

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Answer: f(n)=3^{n-1}

Step-by-step explanation:

Given Recursive formula : a_{n+1} = 3a_n,, a_1=1

Then,  a_2=a_{1+1} = 3a_1=3(1)=3

a_3=a_{2+1} = 3a_2=3(3)=9

a_4=a_{3+1} = 3a_3=3(9)=27

We can write it as : f(n)=3^{n-1}

such that

n      f(n)=3^{n-1}

1       f(1)=3^{1-1}=1

2       f(2)=3^{2-1}=3^1=3

3       f(3)=3^{3-1}=3^2=9

Hence, the required function: f(n)=3^{n-1}

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