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Alex_Xolod [135]
3 years ago
8

Find the area of the triangle ABC given angle A = 45°, b = 8, and c = √2. 4 4√2 8 8√2

Mathematics
1 answer:
Artyom0805 [142]3 years ago
5 0

Answer:

Area  = 4 units²

Step-by-step explanation:

We have given that

Angle A  = 45° , b = 8 and c = √2

We have to calculate the area of the triangle.

The formula to calculate the area is :

A  =  1/2×b×c×sin(A)

Putting values in above formula, we have

A  =  1/2×8×√2 × sin(45)

A  =  1/2×8×√2×1/√2

A  = 4 units² which is the answer.

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yan [13]
Hi, as the elipce has a center at the origion and tha major distance is the axis

\frac{x^2}{a^2} + \frac{y^2}{b^2}  = 1

But, 

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a = 13   ->  Major distance

b = ?  -> 

But, 

\\ b^2 + c^2 = a^2
 \\ 
 \\ b^2 + 12^2 = 13^2
 \\ 
 \\ b^2 + 144 = 169
 \\ 
 \\ b^2 = 169 - 144
 \\ 
 \\ b^2 = 25
 \\ 
 \\ b =  \sqrt{5} 
 \\ 
 \\ b = 5



Then,


\\  \frac{x^2}{(13)^2} +  \frac{y^2}{(5)^2} = 1
 \\ 
 \\ or
 \\ 
 \\  \frac{x^2}{169} +  \frac{y^2}{25} = 1
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3 years ago
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Step-by-step explanation:

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Someone answer this Please
Ainat [17]

The given triangle is a <em><u>Right angled triangle</u></em>,

So, by applying <em><u>Pythagoras theorem</u></em><em><u> </u></em><em><u>:</u></em>

{c}^{2}  =  {12}^{2}  + 9 {}^{2}

=》

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=》

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=》

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=》

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