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Luden [163]
3 years ago
14

If there are 12 eggs in a carton, how many are in 5 cartons?

Mathematics
2 answers:
Elan Coil [88]3 years ago
8 0

Answer:

60

Step-by-step explanation:

12x5 is equal to 60

cupoosta [38]3 years ago
3 0

Answer:

60

Step-by-step explanation:

5 times 12 = 60 so the answer is 60 :)

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Suppose you put $150 in the bank for 2 years at a 3% simple annual interest rate. How much interest will you have earned at the
STALIN [3.7K]

Answer:

$9 in interest for a total of $159

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Two surfers and statistics students collected data on the number of days on which surfers surfed in the last month for 30 longbo
Alisiya [41]

Answer:

Do not reject H0. The mean days surfed for longboarders is significantly larger than the mean days surfed for all shortboarders

Step-by-step explanation:

The null hypothesis is that  the mean days surfed for all long boarders is larger than the mean days surfed for all short boarders

H0:  μL > μs      against the claim Ha:  μL≤ μs

the alternate hypothesis is the mean days surfed for all long boarders isless or equal to  the mean days surfed for all short boarders (because long boards can go out in many different surfing conditions)

The test statistic is

t= x1- x2/  √s1/n1+ s2/n2

1) Calculations

Longboards

Mean

ˉx=∑x/n=4+8+9+4+9+7+9+6+6+11+15+13+16+12+10+12+18+20+15+10+15+19+21+9+22+19+23+13+12+10/30

=377/30

=12.5667

Longboard Variance S2=[∑dx²-(∑dx)²/n]/n-1

=[831-(-13)²/30]/29

=831-5.6333/29

=825.3667/29

=28.4609

Shortboard Mean

ˉx=∑x/n=6+4+6+6+7+7+7+10+4+6+7+5+8+9+4+15+13+9+12+11+12+13+9+11+13+15+9+19+20+11/30

=288/30

=9.6

Shortboard Variance S2=[∑x²-(∑x)²/n]/n-1

=[ 3270-(288)2/30]/29

=3270-2764.8/29

=505.2/29

=17.4207

2) Putting values in the test statistic

t=|x1-x2|/√S²1/n1+S²2/n2

t =|12.5667-9.6|/√28.4609/30+17.4207/30

t =|2.9667|/√0.9487+0.5807

t=|2.9667|/√1.5294

t=|2.9667|/1.2367

t=2.3989

3) Degree of freedom =n1+n2-2=30+30-2=58

4) The critical region is t ≤ t(0.05) (58) =1.6716

5) Since the calculated t= 2.4 does not fall in the critical region t(0.05) (58)  ≤ 1.6716 we do not reject H0.

The p-value is 0.008969. The result is significant at p <0 .05.

6 0
3 years ago
The picture below...
Flura [38]

Answer:

27

Step-by-step explanation:

9+8+10=27

7 0
3 years ago
N a game, four cards are labeled N, S, E, and W. Two tiles are numbered 1 and 2. Two discs are red and blue. A player randomly s
algol [13]

Answer: The probability that the player selects a card with S or E, a tile with 2 and a red disc is given as 0.125 (or 1/8)

Step-by-step explanation: If four cards are labelled N, S, E and W, then that means there are a total of four possible outcomes. Also with tiles numbered 1 and 2 there are a total of two possible outcomes when selecting tiles. Then there are two discs in total (one red and one blue) which means there are a total of two outcomes when selecting discs.

To select a card with S would be calculated as follows;

P(S) = Number of required outcomes/Number of all possible outcomes

P(S) = 1/4

P(S) = 0.25

To select a card with E would likewise be calculated as follows;

P(E) = Number of required outcomes/Number of possible outcomes

P(E) = 1/4

P(E) = 0.25

Therefore, the probability that a player selects a card with S or E is derived as follows;

P(S or E) = P(S) + P(E)

P(S or E) = 0.25 + 0.25

P(S or E) = 0.5

The probability that he selects a tile with 2 written on it is calculated as;

P(T2) = Number of required outcomes/Number of all possible outcomes

P(T2) = 1/2

P(T2) = 0.5

The probability that he will select a red disc is calculated as;

P(R) = Number of required outcomes/Number of possible outcomes

P(R) = 1/2

P(R) = 0.5

Therefore, the probability that the player selects a card with S or E, a tile with 2 and a red disc is calculated as;

P(S or E and T2 and R) = 0.5*0.5*0.5

P(S or E and T2 and R) = 0.125

Hence the probability that the player selects a card with S or E, a tile with 2 and a red disc is 0.125 (or 1/8).

5 0
3 years ago
It takes 4 pounds of apples to make 6 cups of applesauce.
Serjik [45]

Answer:

Step-by-step explanation:

4lbs of apples to 6 cups of apple sauce

we can write this as 2:3

the correct choices: 6:9 and 14:21

4 0
3 years ago
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